David Sang and Graham Jones Solutions for Chapter: Stationary Waves, Exercise 3: Questions

(a) For the arrangement shown in Figure suggest why it is easier to determine accurately the position of a node rather than an antinode.

A stationary sound wave is established between the loudspeaker and the board.

(b) Explain why it is better to measure the distance across several nodes.

For sound waves of frequency $2500 \mathrm{Hz}$, it is found that two nodes are separated by $20 \mathrm{cm}$, with three antinodes between them.

(a) Determine the wavelength of these sound waves.

For sound waves of frequency $2500 \mathrm{Hz}$, it is found that two nodes are separated by $20 \mathrm{cm}$, with three antinodes between them.

(b) Use the wave equation $v=f\lambda$ to determine the speed of sound in air.