R Chandra Solutions for Chapter: Areas of Parallelograms and Triangles, Exercise 1: TEST YOUR SKILLS

Author:R Chandra

R Chandra Mathematics Solutions for Exercise - R Chandra Solutions for Chapter: Areas of Parallelograms and Triangles, Exercise 1: TEST YOUR SKILLS

Attempt the practice questions on Chapter 9: Areas of Parallelograms and Triangles, Exercise 1: TEST YOUR SKILLS with hints and solutions to strengthen your understanding. Full Marks Mathematics 9 solutions are prepared by Experienced Embibe Experts.

Questions from R Chandra Solutions for Chapter: Areas of Parallelograms and Triangles, Exercise 1: TEST YOUR SKILLS with Hints & Solutions

MEDIUM
9th CBSE
IMPORTANT

In the figure, ABCD is a parallelogram and EFCB is a rectangle. Also ALBC.
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Prove that: ar(ABCD)=ar(EFCB)

EASY
9th CBSE
IMPORTANT

In the figure, ABCD is a parallelogram and EFCB is a rectangle. Also ALBC. Prove that:
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arABCD=arBC×AL

MEDIUM
9th CBSE
IMPORTANT

In the adjoining figure, ABCD is a parallelogram such that AECD and CFAD.
If AB=10cm,AE=6cm and CF=8cm, then find AD.
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MEDIUM
9th CBSE
IMPORTANT

In the figure, ABCD is a quadrilateral and BEAC and also BE meets DC produced at E. Show that area of ADE is equal to the area of the quadrilateral ABCD.
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MEDIUM
9th CBSE
IMPORTANT

AB and CD are parallel sides of a trapezium ABCD. Diagonals AC and BD intersect at O. Prove that:
arAOD=ar(BOC).

MEDIUM
9th CBSE
IMPORTANT

If D is midpoint of AB of ABC and P,Q are the points on BC and AB respectively. Such that PDCQ. Then show that arBPQ=12ar(ABC)?

MEDIUM
9th CBSE
IMPORTANT

A rectangle is formed by joining the midpoints of the sides of a rhombus. Show that the area of rectangle is half the area of the rhombus.

MEDIUM
9th CBSE
IMPORTANT

ABCD is a parallelogram. Through A, line AEF is drawn to meet BC at E and DC produced at F. Show that ar(BEF)=ar(DCE).
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