R P Goyal and S P Tripathi Solutions for Chapter: Calorimetry, Exercise 2: EXERCISE-11(B)

A molten metal of mass $150 \mathrm{g}$ is kept at its melting point $800℃.$ When it is allowed to freeze at the same temperature, it gives out $75,000 \mathrm{J}$ of heat energy.
What is the specific latent heat of the metal?

A refrigerator converts $100 \mathrm{g}$ of water at $20℃$ to ice at $–10℃$ in $73.5 \mathrm{minutes}$. Calculate the average rate of heat extraction in $\mathrm{watt}.$ The specific heat capacity of water is $4.2 \mathrm{J} {\mathrm{g}}^{-1} {\mathrm{K}}^{-1}$, Specific latent heat of ice is $336 \mathrm{J} {\mathrm{g}}^{-1}$ and the specific heat capacity of ice is $2.1 \mathrm{J} {\mathrm{g}}^{-1}{\mathrm{K}}^{-1}.$

In an experiment, $17 \mathrm{g}$ of ice is used to bring down the temperature of $40 \mathrm{g}$ of water at $34℃$ to its freezing temperature. The specific heat capacity of water is `$4.2 \mathrm{J} {\mathrm{g}}^{-1} {\mathrm{K}}^{-1}$. Calculate the specific latent heat of ice. State one important assumption made in the above calculation.

Find the result of mixing $10 \mathrm{g}$ of ice at $- 10℃$ with $10 \mathrm{g}$ of water at $10℃$. Specific heat capacity of ice $=2.1 \mathrm{J} {\mathrm{g}}^{-1} {\mathrm{K}}^{-1}$, Specific latent heat of ice is $=336 \mathrm{J} {\mathrm{g}}^{-1}$ and specific heat capacity of water is $=4.2 \mathrm{J} {\mathrm{g}}^{-1} {\mathrm{K}}^{-1}$.

$250 \mathrm{g}$ of water at $30° \mathrm{C}$ is present in a copper vessel of mass $50 \mathrm{g}$. Calculate the mass of ice required to bring down the temperature of the vessel and its contents to $5° \mathrm{C}$.(Take, specific latent heat of fusion of ice = $336\times {10}^3 \mathrm{J} {\mathrm{kg}}^{-1}$, specific heat capacity of copper vessel = $400 \mathrm{J} {\mathrm{kg}}^{-1} °{\mathrm{C}}^{-1}$ and specific heat capacity of water = $4200 \mathrm{J} {\mathrm{kg}}^{-1} °{\mathrm{C}}^{-1}$).

$2 \mathrm{kg}$ of ice melts when water at $100℃$ is poured in a hole drilled in a block of ice. What is the mass of water that was used? Given: Specific heat capacity of water $4200 \mathrm{J} {\mathrm{kg}}^{-1}{\mathrm{K}}^{-1}$, $L_{ice}=336\times {10}^3 \mathrm{J} {\mathrm{kg}}^{-1}.$

Calculate the total amount of heat energy required to convert $100 \mathrm{g}$ of ice at $-10℃$ completely into water at $100℃$. Specific heat capacity of ice $=2.1 \mathrm{J} {\mathrm{g}}^{-1}{\mathrm{K}}^{-1}$, specific heat capacity of water is $4.2 \mathrm{J} {\mathrm{g}}^{-1} {\mathrm{K}}^{-1}$ , specific latent heat of ice is $=336 \mathrm{J} {\mathrm{g}}^{-1}$

The total heat needed to heat $1 \mathrm{kg}$ of ice at $-10º\mathrm{C}$ to water at $100º\mathrm{C}$ is $7.77 \times {10}^5 \mathrm{J}$. Calculate the specific latent heat of ice.

Specific heat capacity of ice $=2100 \mathrm{J} {\mathrm{kg}}^{-1}{\mathrm{K}}^{-1}$

Specific heat capacity of water $=4200 \mathrm{J} {\mathrm{kg}}^{-1}{\mathrm{K}}^{-1}$