Question

Find the equivalent fractions in each group:

$\frac{6}{32}, \frac{4}{16}, \frac{3}{16}, \frac{15}{80}$

Accepted Answer

Given fractions are $\frac{6}{32}, \frac{4}{16}, \frac{3}{16}, \frac{15}{80}$ .

We know that, equivalent fractions are different fractions that are equal to the same number. The numerator and the denominator of a fraction must be multiplied or divided by the same non-zero whole number in order to have equivalent fractions.

Let us consider the first three fractions $\frac{6}{32}, \frac{4}{16} and \frac{3}{16}$ .

The above group of fractions are not equivalent as $16 \times 2 = 32$ but $4 \times 2 \neq 6$ .

Also, $\frac{4}{16} and \frac{3}{16}$ are like fractions as their denominators are same.

Thus, $\frac{6}{32}, \frac{4}{16} and \frac{3}{16}$ are not equivalent fractions.

Now, let us consider $\frac{4}{16}, \frac{3}{16} and \frac{15}{80}$ .

The above group of fractions are not equivalent as, $\frac{4}{16} and \frac{3}{16}$ are like fractions.

Let us now consider the fractions $\frac{3}{16}, \frac{15}{80} and \frac{6}{32}$ .

The above fractions are equivalent as,

$\frac{3}{16} = \frac{3 \times 2}{16 \times 2} = \frac{6}{32} \frac{3}{16} = \frac{3 \times 5}{16 \times 5} = \frac{15}{80}$

Thus, the required group is $\frac{3}{16}, \frac{6}{32} and \frac{15}{80}$ .

Rahul Sofat Solutions for Chapter: Fractions, Exercise 5: REVIEW EXERCISES

Rahul Sofat Mathematics Solutions for Exercise - Rahul Sofat Solutions for Chapter: Fractions, Exercise 5: REVIEW EXERCISES

Questions from Rahul Sofat Solutions for Chapter: Fractions, Exercise 5: REVIEW EXERCISES with Hints & Solutions

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