C D → = - 2 4 . Write down the column vector D C → .

Here C D → = - 2 4 and we know that D C → = - C D → ⇒ D C → = - - 2 4 ⇒ D C → = 2 - 4

Point A has position vector 4 2 . A B → = 2 - 6 and B C → = - 3 5 . Show points A , B and C on suitable axes.

Given: Positive vector of A = 4 2 , A B → = 2 - 6 and B C → = - 3 5 . Let the position vector of A → , B → and C → be O A → , O B → and O C → . Then, A B → = O B → - O A → ⇒ 2 - 6 = O B → - 4 2 ⇒ O B → = 2 - 6 + 4 2 ⇒ O B → = 6 - 4 and B C → = O C → - O B → ⇒ - 3 5 = O C → - 6 - 4 ⇒ O C → = - 3 5 + 6 - 4 ⇒ O C → = 3 1 So, the required points are A 4 , 2 , B 6 , - 4 and C 3 , 1 .

Point A has position vector 4 2 . A B → = 2 - 6 and B C → = - 3 5 . Write down the position vector of point C .

Given: Positive vector of A = 4 2 , A B → = 2 - 6 and B C → = - 3 5 . Let the position vector of A → , B → and C → be O A → , O B → and O C → . Then, A B → = O B → - O A → ⇒ 2 - 6 = O B → - 4 2 ⇒ O B → = 2 - 6 + 4 2 ⇒ O B → = 6 - 4 and B C → = O C → - O B → ⇒ - 3 5 = O C → - 6 - 4 ⇒ O C → = - 3 5 + 6 - 4 ⇒ O C → = 3 1 So, the position vector of C is 3 1 .

E M B I B E

Extended MYP Mathematics A Concept based approach Years 4 & 5>Is Something Networking?>Chapter 19 - Vectors>Practice 1

Rose Harrison, Clara Huizink, Aidan Sproat Clements and, Marlene Torres Skoumal Solutions for Exercise 5: Practice 1

Author:Rose Harrison, Clara Huizink, Aidan Sproat Clements & Marlene Torres Skoumal

Rose Harrison Mathematics Solutions for Exercise - Rose Harrison, Clara Huizink, Aidan Sproat Clements and, Marlene Torres Skoumal Solutions for Exercise 5: Practice 1

Attempt the practice questions from Exercise 5: Practice 1 with hints and solutions to strengthen your understanding. Extended MYP Mathematics A Concept based approach Years 4 & 5 solutions are prepared by Experienced Embibe Experts.

Questions from Rose Harrison, Clara Huizink, Aidan Sproat Clements and, Marlene Torres Skoumal Solutions for Exercise 5: Practice 1 with Hints & Solutions

EASY

MYP:4-5

IMPORTANT

Extended MYP Mathematics A Concept based approach Years 4 & 5>Chapter 19 - Vectors>Practice 1>Q 2

On this grid find two points so that the translation from one to other is $(\begin{matrix} 4 \\ - 3 \end{matrix})$ .

Question Image

EASY

MYP:4-5

IMPORTANT

Extended MYP Mathematics A Concept based approach Years 4 & 5>Chapter 19 - Vectors>Practice 1>Q 4

Write the vector that translates $P (4, 6)$ to $Q (11, 3)$

EASY

MYP:4-5

IMPORTANT

Extended MYP Mathematics A Concept based approach Years 4 & 5>Chapter 19 - Vectors>Practice 1>Q 4

Write the vector that translates $R (11, - 2)$ to $S (7, 5)$

EASY

MYP:4-5

IMPORTANT

Extended MYP Mathematics A Concept based approach Years 4 & 5>Chapter 19 - Vectors>Practice 1>Q 4

Write the vector that translates $T (- 5, 1)$ to $U (- 6, - 3)$

EASY

MYP:4-5

IMPORTANT

Extended MYP Mathematics A Concept based approach Years 4 & 5>Chapter 19 - Vectors>Practice 1>Q 5

$\vec{C D} = (\begin{matrix} - 2 \\ 4 \end{matrix})$ . Write down the column vector $\vec{D C}$ .

MEDIUM

MYP:4-5

IMPORTANT

Extended MYP Mathematics A Concept based approach Years 4 & 5>Chapter 19 - Vectors>Practice 1>Q 6

Point $A$ has position vector $(\begin{matrix} 4 \\ 2 \end{matrix})$ . $\vec{A B} = (\begin{matrix} 2 \\ - 6 \end{matrix})$ and $\vec{B C} = (\begin{matrix} - 3 \\ 5 \end{matrix})$ .

Show points $A, B$ and $C$ on suitable axes.

MEDIUM

MYP:4-5

IMPORTANT

Extended MYP Mathematics A Concept based approach Years 4 & 5>Chapter 19 - Vectors>Practice 1>Q 6

Point $A$ has position vector $(\begin{matrix} 4 \\ 2 \end{matrix})$ . $\vec{A B} = (\begin{matrix} 2 \\ - 6 \end{matrix})$ and $\vec{B C} = (\begin{matrix} - 3 \\ 5 \end{matrix})$ .