S C Kheterpal, S N Dhawan and, P N Kapil Solutions for Chapter: Equilibrium in Physical and Chemical Processes, Exercise 24: Competition Focus

Author:S C Kheterpal, S N Dhawan & P N Kapil

S C Kheterpal Chemistry Solutions for Exercise - S C Kheterpal, S N Dhawan and, P N Kapil Solutions for Chapter: Equilibrium in Physical and Chemical Processes, Exercise 24: Competition Focus

Attempt the practice questions on Chapter 8: Equilibrium in Physical and Chemical Processes, Exercise 24: Competition Focus with hints and solutions to strengthen your understanding. Pradeep's Chemistry Vol 1 solutions are prepared by Experienced Embibe Experts.

Questions from S C Kheterpal, S N Dhawan and, P N Kapil Solutions for Chapter: Equilibrium in Physical and Chemical Processes, Exercise 24: Competition Focus with Hints & Solutions

MEDIUM
11th CBSE
IMPORTANT

Which of the following lines correctly show the temperature dependence of equilibrium constant K, for an exothermic reaction?
Question Image

MEDIUM
11th CBSE
IMPORTANT

Which of the following are reversible reactions?

MEDIUM
11th CBSE
IMPORTANT

Which of the following statements are wrong?

MEDIUM
11th CBSE
IMPORTANT

The equilibrium SO2Cl2 (g)SO2 (g) + Cl2 (g) is attained at 25°C in a closed container and inert gas helium is introduced. Which of the following statements are correct?

HARD
11th CBSE
IMPORTANT

For the reaction PCl5 (g)PCl3 (g) + Cl2 (g), the forward reaction at constant temperature is favoured by

HARD
11th CBSE
IMPORTANT

The equilibrium 2CuI  Cu0 + CuII in aqueous medium at 25°C shifts towards the left in the presence of

MEDIUM
11th CBSE
IMPORTANT

The thermal dissociation equilibrium of CaCO3 (s) is studied under different conditions.
CaCO3 (s)CaO (s) + CO2 (g) 
For this equilibrium, the correct statement (s) is (are)

MEDIUM
11th CBSE
IMPORTANT

For the following question, enter the correct numerical value, (in decimal-notation, truncated/rounded-off to the second decimal place, e.g., 6.25, 7.00, -0.33, 30.27, -127.30).

The approach of the following equilibrium was observed kinetically from both directions :
PtCl42-+ H2O  Pt(H2O)Cl3-+Cl-
At 25°C, it was found that d [PtCl-]4dt=(3.90×10-5 s-1) [PtCl42-]-(2·1×10-3 L mol-1 s-1) [Pt(H2O)Cl3-][Cl-] 
What will be the value of the equilibrium constant when fourth Cl- ion is complexed, i.e., for the step involving backward reaction?