Sarvesh K Verma Solutions for Chapter: Geometry, Exercise 2: Introductory Exercise

In $△ABC$, $AB=5 \mathrm{cm}$, $AC=7 \mathrm{cm}$. If $AD$ is the angle bisector of$\angle A$ . Then $BD : CD$ is-

The incentre of a triangle is determined by

If in a $∆\mathrm{ABC},\text{'}{\mathrm{S}}^{\text{'}}$ is the circumcentre, then:

In a right angled $∆\mathrm{ABC},\angle \mathrm{C}=90°$ and $\mathrm{CD}$ is the perpendicular on hypotenuse $\mathrm{AB}$ if $\mathrm{BC}=15 \mathrm{cm}$ and $\mathrm{AC}=20 \mathrm{cm}$, then $\mathrm{CD}$ is equal to :

The internal bisector of$\angle B$ and $\angle C$ of$△ABC$ meet at O. If $\angle A = {80}^0$ , then $\angle BOC$ is-

$\mathrm{ABC}$ is a triangle and $\mathrm{DE}$ is drawn parallel to $\mathrm{BC}$ cutting other sides $AB$ and $AC$ at $\mathrm{D} \& \mathrm{E}$ respectively. If $\mathrm{AB}$$= 3.6 \mathrm{cm}$, $\mathrm{AC}$ $= 2.4 \mathrm{cm}$ and $\mathrm{AD}$$= 2.1 \mathrm{cm}$ then $\mathrm{AE}$ is _____

ABC is an isoceles triangles with AB = AC, side BA is produced to D such that AB = AD. Find ∠BCD.

In $\Delta ABC$. $A{B}^2+A{C}^2 = 2500$ $c{m}^2$ and median $AD=25$ $cm$. Find $BC$ ?