A P Shreelatha and Neetu Singh Solutions for Chapter: Work and Energy, Exercise 6: EXERCISES

Author:A P Shreelatha & Neetu Singh

A P Shreelatha Physics Solutions for Exercise - A P Shreelatha and Neetu Singh Solutions for Chapter: Work and Energy, Exercise 6: EXERCISES

Attempt the practice questions on Chapter 5: Work and Energy, Exercise 6: EXERCISES with hints and solutions to strengthen your understanding. Secondary Physics solutions are prepared by Experienced Embibe Experts.

Questions from A P Shreelatha and Neetu Singh Solutions for Chapter: Work and Energy, Exercise 6: EXERCISES with Hints & Solutions

MEDIUM
9th CBSE
IMPORTANT

A lift carries 5 persons with an average mass of 60 kg to a height of 27 m in 9 seconds at a constant speed. What is the power (in watt) of the lift? Take g=9.8 m s-2
(Solution should contain only magnitude of power).

EASY
9th CBSE
IMPORTANT

A person lifts 80 kg suitcase from the ground and puts on his head 2 m above the ground. Calculate the work done by the person.

HARD
9th CBSE
IMPORTANT

The power of heart which beats 72 times in a minute is 1.2 kW. Calculate the work done by the heart for each heartbeat (in joules).

MEDIUM
9th CBSE
IMPORTANT

A horizontal force of 50 N displaces an object of mass 100 kg. Calculate the work done by the force in 8 seconds.

HARD
9th CBSE
IMPORTANT

A 500 W electric bulb lighted for 2 hours everyday and an electric motor of 0.5 horse power is used for 2 hours everyday. Calculate the cost of using the bulb and the motor for 30 days, if the cost of electrical energy is three rupees per unit.

MEDIUM
9th CBSE
IMPORTANT

An electric heater of 1000 W is used everyday for 70 minutes. Calculate the units of electrical energy this heater will consume in 30 days of use.

MEDIUM
9th CBSE
IMPORTANT

A bag of wheat weighing 8 kg is lifted through a height of 12 m in 5 seconds with a constant velocity. Calculate the power developed during the process.

MEDIUM
9th CBSE
IMPORTANT

A force of 200 N acting at an angle of 45° to the horizontal does a work of 45000 J. Calculate the displacement caused by the force in horizontal direction. (Take cos 45°=0 .7071)