DPP

Author:Seema Saini

Seema Saini Chemistry Solutions for Exercise - DPP

Simple step-by-step solutions to DPP questions of Qualitative Inorganic Salt Analysis from Chapterwise/Topicwise Daily Practice Problems (DPP) Inorganic Chemistry Part - 2 JEE Main & Advanced. Also get 3D topic explainers, cheat sheets, and unlimited doubts solving on EMBIBE.

Questions from DPP with Hints & Solutions

MEDIUM
JEE Main
IMPORTANT

Three samples of the same salts are taken separately. Excess of NH4OH gives white precipitate with the first sample. The second sample gives white precipitate with NaCl. The third sample gives black precipitate when H2S gas is passed through the solution. The possible salt is

MEDIUM
JEE Main
IMPORTANT

In the borax bead test of Co2+, the blue colour of bead is due to the formation of:

MEDIUM
JEE Main
IMPORTANT

Aq. Solution of 'X' reacts with Na3CoNO26 to form yellow precipitate. The cation(s) present in 'X' is/are:

 

MEDIUM
JEE Main
IMPORTANT

Potassium chromate solution is added to aqueous solutions of metal nitrate. The yellow precipitate thus obtained is insoluble in acetic acid. These are subjected to flame test, flame colour of individual precipitate is/are

HARD
JEE Main
IMPORTANT

Which of the following aqueous solution of cation(s) give(s) white precipitate with NaOH and NH4OH solution and formed precipitate is/are further completely dissolved in one of the excess reagent?

MEDIUM
JEE Main
IMPORTANT

Saturated solution of SO2 is heated at 150°C in a closed container. The product obtained is treated with BaCl2 solution. What is/are the most suitable observation(s)?

HARD
JEE Main
IMPORTANT

Cu2+ and Cd2+ can be distinguished by which of the following reagent(s).

HARD
JEE Main
IMPORTANT

White precipitate in test tube "c" and the soluble complex formed from white precipitate with the hypo solution is/are (This question from book is not having information hence the question is reframed as given below).

A salt solution when treated with ammonia forms a white precipitate. On addition of excess ammonia, the precipitate is insoluble. When the same solution is treated with hypo white precipitate is formed; when in excess amount of hypo is completely soluble. When the white precipitate formed from treatment of hypo is heated, it turns black. Identify the white precipitate and its soluble complex.