It is a saturated branched alkyl hydrocarbon. The longest chain is selected first. The longest chain here is ten carbon atoms long. As a result, the word root 'dec' is used. Since the substituent is given the lowest number, the numbering begins at the left end of the chain. In this chain, two substituents are present at the position 4 and 5 . Isopropyl group is present at the position 4 , while the secondary butyl present at the position 5 . The secondary butyl is given priority based on alphabetical order. So, the name of the compound is 5 - secbuytl - 4 - isopropyldecane.

It is an unsaturated straight hydrocarbon chain that contains both double and triple bonds. Enynes is the name given to this system. Naming pattern for enynes: Alk + Location of en + Location of yne Since the compound's longest chain contains eight carbon atoms, the term root oct is used. The double bond takes priority over the triple bond, so the double bond in the chain is given the lowest numbering. The system's primary suffixes are double and triple bonds. So, the name of the above compound is oct - 2 - en - 5 - yne.

lUPAC name of the compound is

3 , 3 ‐ Diethenyl ‐ 1 , 4 ‐ pentadiene

E M B I B E

Chapterwise/Topicwise Daily Practice Problems (DPP) Organic Chemistry Part 1 JEE Main & Advanced>Chapter 1 - Classification and Nomenclature Of Organic Compounds>DPP

Seema Saini Solutions for Chapter: Classification and Nomenclature Of Organic Compounds, Exercise 2: DPP

Author:Seema Saini

Seema Saini Chemistry Solutions for Exercise - Seema Saini Solutions for Chapter: Classification and Nomenclature Of Organic Compounds, Exercise 2: DPP

Attempt the free practice questions on Chapter 1: Classification and Nomenclature Of Organic Compounds, Exercise 2: DPP with hints and solutions to strengthen your understanding. Chapterwise/Topicwise Daily Practice Problems (DPP) Organic Chemistry Part 1 JEE Main & Advanced solutions are prepared by Experienced Embibe Experts.