Find the value of x ∘ in the following figures:

Using the theorem the angle subtended by an arc of a circle at the centre is double the angle subtended by it at any point on the remaining part of a circle. ∠ P O R = 2 ∠ P Q R x ∘ = 2 × 50 ∘ x ∘ = 100 ∘

Find the value of x ∘ in the following figures:

Using the theorem the angle subtended by an arc of a circle at the centre is double the angle subtended by it at any point on the remaining part of a circle. ∠ M N L = 1 2 Reflex ∠ M O L = 1 2 × 260 ∘ x ∘ = 130 ∘

Find the value of x ∘ in the following figures:

Using the theorem the angle subtended by an arc of a circle at the centre is double the angle subtended by it at any point on the remaining part of a circle. X Y is the diameter of the circle. Therefore ∠ X Z Y = 90 ∘ (Angle on a semi - circle) In ∆ X Y Z x ∘ + 63 ∘ + 90 ∘ = 180 ∘ x ∘ = 27 ∘

Find the value of x ∘ in the following figures:

Using the theorem the angle subtended by an arc of a circle at the centre is double the angle subtended by it at any point on the remaining part of a circle. O A = O B = O C (Radii) In ∆ O A C ∠ O A C = ∠ O C A = 20 ∘ In ∆ O B C , ∠ O B C = ∠ O C B = 35 ∘ (angles opposite to equal sides are equal) ∠ A C B = ∠ O C A + ∠ O C B x ∘ = 20 ∘ + 35 ∘ x ∘ = 55 ∘

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Mathematics Standard 9>Chapter 4 - Geometry>Exercise

Exercise

Author:Tamil Nadu Board

Tamil Nadu Board Mathematics Solutions for Exercise

Simple step-by-step solutions to Exercise questions of Geometry from Mathematics Standard 9. Also get 3D topic explainers, cheat sheets, and unlimited doubts solving on EMBIBE.

Questions from Exercise with Hints & Solutions

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9th Tamil Nadu Board

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Mathematics Standard 9>Chapter 4 - Geometry>Exercise>Q 17

If one angle of a cyclic quadrilateral is $75 °$ then the opposite angle is

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9th Tamil Nadu Board

IMPORTANT

Mathematics Standard 9>Chapter 4 - Geometry>Exercise>Q 18

In the figure, $A B C D$ is a cyclic quadrilateral in which $D C$ produced to $E$ and $C F$ is drawn parallel to $A B$ such that $∠ A D C = 80 °$ and $∠ E C F = 20 °,$ then $∠ B A D =$ ?