Draw the graph of x 2 + y 3 = 1 .

Given equation is x 2 + y 3 = 1 . Steps for drawing the graph: ∙ Make the subject of formula as y . ∙ Choose three values for x and find the corresponding values of y . ∙ Display the values of x and y in a table. ∙ Plot the points and draw the graph. Now, x 2 + y 3 = 1 ⇒ y 3 = 1 - x 2 y = 3 2 - x 2 x 0 2 4 y = 3 2 - x 2 3 0 - 3 Draw x -axis and y -axis, choose suitable scale for the axes. x -axis: 1 cm = 1 unit , y -axis: 1 cm = 1 unit Plot the points 0 , 3 , 2 , 0 , 4 , - 3 and draw the graph. Write the equation of the line. Thus, we obtained the graph of the linear equation in two variables x 2 + y 3 = 1 and it is a line.

Draw the graph of x 3 - y 2 = 1 .

Given equation is x 3 - y 2 = 1 . Steps for drawing the graph: ∙ Make the subject of formula as y . ∙ Choose three values for x and find the corresponding values of y . ∙ Display the values of x and y in a table. ∙ Plot the points and draw the graph. Now, x 3 - y 2 = 1 ⇒ y 2 = x 3 - 1 y = 2 x - 3 3 x 0 3 6 y = 2 x - 3 3 - 2 0 2 Draw x -axis and y -axis, choose suitable scale for the axes. x -axis: 1 cm = 1 unit , y -axis: 1 cm = 1 unit Plot the points 0 , - 2 , 3 , 0 , 6 , 2 and draw the graph. Write the equation of the graph. Thus, we obtained the graph of the linear equation in two variables x 3 - y 2 = 1 and it is a line.

E M B I B E

ICSE Skills In Mathematics>Algebra>Chapter 21 - Coordinate System and Graphs>EXERCISE 21(B)

V K Raman and S N Sharma Solutions for Exercise 2: EXERCISE 21(B)

Author:V K Raman & S N Sharma

V K Raman Mathematics Solutions for Exercise - V K Raman and S N Sharma Solutions for Exercise 2: EXERCISE 21(B)

Attempt the practice questions from Exercise 2: EXERCISE 21(B) with hints and solutions to strengthen your understanding. ICSE Skills In Mathematics solutions are prepared by Experienced Embibe Experts.