V K Sally and R Goel Solutions for Chapter: Gravitation, Exercise 6: EXERCISE

The average distance between the earth and the sun is $1.5\times {10}^{11 }\mathrm{m}$. If the mass of the earth is $6\times 10{ }^{24 }\mathrm{kg}$ and the sun is $2\times 10{ }^{30 }\mathrm{kg}$ the force of gravitation between them is: (Take, $G = 6.67\times {10}^{-11} \mathrm{N} {\mathrm{m}}^2 {\mathrm{kg}}^{-2}$) 

The average distance between the earth and the moon $3.84\times {10}^5 \mathrm{km}$. If the mass of the moon $7.4\times {10}^{22} \mathrm{kg}$ and that of earth is $6\times {10}^{24} \mathrm{kg}$. The gravitational force of the moon on earth is: (Take, $G = 6.67\times {10}^{-11} \mathrm{N} {\mathrm{m}}^2 {\mathrm{kg}}^{-2}$) 

The mass of the earth is $6\times 10{ }^{24 }\mathrm{kg}$, radius $6.4\times 10{ }^{6 }\mathrm{m}$ and $G=6.7\times {10}^{-11} \mathrm{N} {\mathrm{m}}^2 {\mathrm{kg}}^{-2}$. The acceleration due to gravity on the surface of the earth is:  

The mass of the moon is $7.36\times {10}^{22} \mathrm{kg}$ and the radius is $1.74\times {10}^6 \mathrm{m}$. The mass of the earth is $5.98\times {10}^{24} \mathrm{kg}$ and radius is $6.37\times {10}^6 \mathrm{m}$. The ratio of the weight of a body on the moon to the weight of the body on the earth is: [Take, $G=6.67\times {10}^{-11} \mathrm{N} {\mathrm{m}}^2 {\mathrm{kg}}^{-2}$] 

The radius of earth is $6400 \mathrm{km}$. At what height the value of $g$ will be $60\%$.

If radius of earth is $R$, at what height from the surface of earth, the weight of the body becomes half?

A meteor passes near the earth at a height equal to $3$ times the radius of earth. If $g$ is the acceleration due to gravity on its surface, the acceleration experienced by the meteor in terms of $g$ is.

Is mass a scalar quantity or a vector quantity?