West Bengal Board Solutions for Chapter: Occurence of Carbon and its Compounds in Nature, Exercise 4: Exercise 4

Reaction of metal carbonate and bicarbonate with dilute acid to produce ${\mathrm{CO}}_2$ gas.

${\mathrm{CaCO}}_3+2\mathrm{HCl}=\mathrm{\_\_\_\_\_}+{\mathrm{CO}}_2+{\mathrm{H}}_2\mathrm{O}$

Reaction of metal carbonate and bicarbonate with dilute acid to produce ${\mathrm{CO}}_2$ gas.

${\mathrm{Na}}_2{\mathrm{CO}}_3+{\mathrm{H}}_2{\mathrm{SO}}_4=\mathrm{\_\_\_\_\_}+{\mathrm{CO}}_2+{\mathrm{H}}_2\mathrm{O}.$

Complete the reaction of metal carbonate and bicarbonate with dilute acid to produce ${\mathrm{CO}}_2$ gas given below:

${\mathrm{MgCO}}_3+\mathrm{\_\_\_\_\_}={\mathrm{MgCl}}_2+{\mathrm{CO}}_2+\mathrm{\_\_\_\_\_}$.

Reaction of metal carbonate and bicarbonate with dilute acid to produce ${\mathrm{CO}}_2$ gas.

${\mathrm{NaHCO}}_3+\mathrm{HCl}=\mathrm{NaCl}+\mathrm{\_\_\_\_\_}+{\mathrm{H}}_2\mathrm{O}$..

${\mathrm{PbSO}}_4, {\mathrm{PbCl}}_2$ and ${\mathrm{CaSO}}_4$ are insoluble in water. Is it possible to get ${\mathrm{CO}}_2$ gas by the reaction of ${\mathrm{PbCO}}_3$ with dilute $\mathrm{HCl}$ or ${\mathrm{H}}_2{\mathrm{SO}}_4$?

Production of ${\mathrm{CO}}_2$ gas by heating metal carbonates or bicarbonates

${\mathrm{PbCO}}_3\stackrel{\mathrm{high} \mathrm{temperature}}{\to }\mathrm{\_\_\_\_\_}+\mathrm{\_\_\_\_\_}$

Production of ${\mathrm{CO}}_2$ gas by heating metal carbonates or bicarbonates

$\mathrm{Ca}({\mathrm{HCO}}_3{)}_2\stackrel{\mathrm{normal} \mathrm{temperature}}{\to }\mathrm{\_\_\_\_}+\mathrm{\_\_\_\_\_}$

How can the following conditions influence the production of carbon dioxide?