If 0 . 05 g of urea is dissolved in 5 g of water, then

its molality will be greater than molarity

its molarity will be greater than molality

molarity and molality will be same

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$1 g$ mole of oxalic acid is dissolved in $2$ litre of solution. The concentration of solution is

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Important Questions on Solutions

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Chemistry>Physical Chemistry>Solutions>Methods of Expressing Concentration of Solutions

The molarity of the solution prepared by dissolving

6.3 g

of oxalic acid

(H_{2} C_{2} O_{4} \cdot 2 H_{2} O)

250 mL

of water in

mol L^{- 1}

x \times 10^{- 2} .

The value of

x

is _________ . (Nearest integer)
[Atomic mass :

H : 1.0, C : 12.0, 0 : 16.0 J

]

MEDIUM

Chemistry>Physical Chemistry>Solutions>Methods of Expressing Concentration of Solutions

The molarity of a solution obtained by mixing

750 mL

0.5 (M) HCl

with

250 mL

2 (M) HCl

will be

HARD

Chemistry>Physical Chemistry>Solutions>Methods of Expressing Concentration of Solutions

Density of

3 M

solution of

NaCl

1.25 g / mL .

Calculate the volume of water required to make

1000 mL

of this

NaCl

solution. [Consider the density of water as

1 g / mL] .

MEDIUM

Chemistry>Physical Chemistry>Solutions>Methods of Expressing Concentration of Solutions

500 ml

{CaCl}_{2}

solution contains

3.01 \times 10^{22}

chloride ions, molarity of the solution will be

EASY

Chemistry>Physical Chemistry>Solutions>Methods of Expressing Concentration of Solutions

Which of the following statements is true?

$1$ ) $200 mL$ of $0.2 M$ $NaOH$ has a same number of moles of solute as $1000 mL$ of $1 M NaOH$ .
$2$ ) $200 mL$ of $1 M NaOH$ has a same number of moles as $1000 mL$ of $0.2 M NaOH$ .
$3$ ) $100 mL$ of $0.2 M NaOH$ has a same number of moles as $1000 mL$ of $1 M NaOH$ .
$4$ ) $2000 mL$ of $0.2 M NaOH$ has a same number of moles as $1000 mL$ of $1 M NaOH$ .

EASY

Chemistry>Physical Chemistry>Solutions>Methods of Expressing Concentration of Solutions

If $80 g$ of copper sulphate ${CuSO}_{4} \cdot 5 H_{2} O$ is dissolved in deionised water to make $5 L$ of solution. The concentration of the copper sulphate solution is $x \times 10^{- 3} mol L^{- 1} .$ The value of $x$ is _____.

$[Atomic masses Cu : 63.54 u, S : 32 u, O : 16 u, H : 1 u]$

MEDIUM

Chemistry>Physical Chemistry>Solutions>Methods of Expressing Concentration of Solutions

Calculate the molarity of a solution of

30 g

Co {({NO}_{3})}_{2} . 6 H_{2} O

4.3 L

of solution ? Consider atomic mass of

Co = 59, N = 14, O = 16, H = 1

EASY

Chemistry>Physical Chemistry>Solutions>Methods of Expressing Concentration of Solutions

8 gm

NaOH

is dissolved in

250 ml

water. Determine the molarity of the solution.

EASY

Chemistry>Physical Chemistry>Solutions>Methods of Expressing Concentration of Solutions

4.5 g

of compound

A (M . W . = 90)

was used to make

250 mL

of its aqueous solution. The molarity of the solution in

M

x \times 10^{- 1} .

The value of

x

is_____ (Rounded off to the nearest integer)

HARD

Chemistry>Physical Chemistry>Solutions>Methods of Expressing Concentration of Solutions

A $6.50$ molal solution of $KOH (aq .)$ has a density of $1.89 g {cm}^{- 3}$ . The molarity of the solution is $mol {dm}^{- 3}$ . (Round off to the Nearest Integer).

[Atomic masses: $K : 39.0 u; O : 16.0 u; H : 1.0 u$ ]

MEDIUM

Chemistry>Physical Chemistry>Solutions>Methods of Expressing Concentration of Solutions

Concentrated ${HNO}_{3}$ is $63 % {HNO}_{3}$ by mass and has a density of $1.4 g / ml .$ How many milliliters of this solution are required to prepare $250 ml$ of a $1.2 M {HNO}_{3}$ solution ?

MEDIUM

Chemistry>Physical Chemistry>Solutions>Methods of Expressing Concentration of Solutions

The mole fraction of urea in an aqueous urea solution containing

900 g

of water is

0.05

. If the density of the solution is

1.2 g {c m}^{- 3}

, the molarity of urea solution is _______. (Round off the answer to the nearest decimal)
(Given data: Molar masses of urea and water are

60 g {m o l}^{- 1}

and

18 g {m o l}^{- 1}

, respectively)

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Chemistry>Physical Chemistry>Solutions>Methods of Expressing Concentration of Solutions

1.2 g

Mg

is treated with

100 mL

1 M

H_{2} {SO}_{4}

. Molar concentration of the

H_{2} {SO}_{4}

solution after complete reaction will be

EASY

Chemistry>Physical Chemistry>Solutions>Methods of Expressing Concentration of Solutions

100 mL

{Na}_{3} {PO}_{4}

solution contains

3.45 g

of sodium. The molarity of the solution is .....

\times 10^{- 2} mol L^{- 1}

. (Nearest integer)
[Atomic Masses -

Na : 23.0 u, O : 16.0 u, P : 31.0 u]

EASY

Chemistry>Physical Chemistry>Solutions>Methods of Expressing Concentration of Solutions

0.05 g

of urea is dissolved in

5 g

of water, then

EASY

Chemistry>Physical Chemistry>Solutions>Methods of Expressing Concentration of Solutions

When the temperature of a solution increases then-

EASY

Chemistry>Physical Chemistry>Solutions>Methods of Expressing Concentration of Solutions

4.0 grams of $NaOH$ (Molar mass = $40.0 g {mol}^{- 1}$ ) is dissolved in $500 {cm}^{3}$ of water. What is the molarity of $NaOH$ solution?

MEDIUM

Chemistry>Physical Chemistry>Solutions>Methods of Expressing Concentration of Solutions

If the concentration of glucose

(C_{6} H_{12} O_{6})

in blood is

0.72 g L^{- 1},

the molarity of glucose in blood is

- \times 10^{- 3} M

(Nearest integer):

[

Given : Atomic mass of

C = 12, H = 1, O = 16 u]

MEDIUM

Chemistry>Physical Chemistry>Solutions>Methods of Expressing Concentration of Solutions

A solution of two components containing

n_{1}

moles of the

1^{st}

component and

n_{2}

moles of the

2^{nd}

component is prepared.

M_{1}

and

M_{2}

are the molecular weights of component 1 and 2 respectively. If

d

is the density of the solution in

{gml}^{- 1}, C_{2}

is the molarity and

x_{2}

is the mole fraction of the

2^{nd}

component, then

C_{2}

can be expressed as :

MEDIUM

Chemistry>Physical Chemistry>Solutions>Methods of Expressing Concentration of Solutions

The molarity of

{H N O}_{3}

in a sample which has density

1.4 g / m L

and mass percentage of

63 %

is ________ (Molecular Weight of

{H N O}_{3} = 63

)

1 g mole of oxalic acid is dissolved in 2 litre of solution. The concentration of solution is

Important Questions on Solutions

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$1 g$ mole of oxalic acid is dissolved in $2$ litre of solution. The concentration of solution is