HARD
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18 g of non volatile soluteMolecular mass=180 dissolved in 100 g of water. Calculate its vapour pressure at 20C if vapour pressure of water at 20C is 17.535 mm.

Important Questions on Solutions

MEDIUM
Vapour pressure of water at 293 K is 17.535 mm Hg. Calculate the vapour pressure of water at 293 K when 25 g of glucose is dissolved in 450 g of water.
HARD
Which of the following statements about the composition of the vapour over an ideal 1 : 1 molar mixture of benzene and toluene is correct? Assume that the temperature is constant at 25oC . (Given vapour pressure data at 25oC , benzene = 12.8 kPa, toluene = 3.85 kPa)
EASY
9 gram anhydrous oxalic acid (mol. Wt. = 90) was dissolved in 9.9 moles of water. If vapour pressure of pure water is P1o the vapour pressure of solution is
HARD
Liquids A and B form ideal solution for all compositions of A and B at 25C. Two such solutions with 0.25 and 0.50 mole fractions of A have the total vapor pressures of 0.3 and 0.4 bar, respectively. What is the vapor pressure of pure liquid B in bar?
HARD
Liquids A and B form an ideal solution in the entire composition range. At 350K, the vapour pressure of pure A and pure B are 7×103Pa and 12×103Pa , respectively. The composition of the vapour in equilibrium with a solution containing 40 mole percent of A at this temperature is:
MEDIUM
An open beaker of water in equilibrium with water vapour is in a sealed container. When a few grams of glucose are added to the beaker of water, the rate at which water molecules :
MEDIUM
Liquid M and liquid N form an ideal solution. The vapour pressures of pure liquids M and N are 450 and 700 mmHg, respectively, at the same temperature. Then correct statements is:
( xM=Mole fraction of 'M' in solution;
xN=Mole fraction of 'N'in solution;
yM=Mole fraction of 'M' in vapour phase;
yN=Mole fraction of 'N' in vapour phase; )
MEDIUM
A solution contains 5 moles of X and 5 moles of Y, and has a normal boiling point of 90°C. The vapor pressure of pure X is 300 mm Hg. What is the vapor pressure of pure Y at this temperature?
MEDIUM
A solution is prepared by mixing 8.5 g of CH2Cl2 and 11.95 g of CHCl3 . If vapour pressure of CH2Cl2 and CHCl3 at 298K are 415 and 200 mm Hg respectively, the mole fraction of CHCl3 in vapour form is: Molar mass of Cl=35.5 g mol-1
MEDIUM
For a solution formed by mixing liquids L and M, the vapour pressure of L plotted against the mole fraction of M in solution is shown in the following figure, Here, XL and XM represent mole fractions of L and M, respectively, in the solution. The correct statement(s) applicable to this system is(are) -

Question Image
MEDIUM
38.4 g of unknown substance (molar mass 384 g mol-1) and 116 g of acetone is used to prepare a solution at 313 K. If vapour pressure of pure acetone (molar mass 58 g mol-1) is 0.842 atmosphere, what is the vapour pressure of solution ?
MEDIUM
A solution at 20oC is composed of 1.5 mol of benzene and 3.5 mol of toluene. If the vapour pressure of pure benzene and pure toluene at this temperature are 74.7 torr and 22.3 torr respectively, then the total vapour pressure of the solution and the benzene mole fraction in equilibrium with it will be, respectively:
MEDIUM
How many grams of glucose are required to prepare an aqueous solution of glucose having a vapor pressure of 23.324 mm Hg at 25°C in 100 g of water? The vapour pressure of pure water at 25°C is 23.8 mm Hg.
MEDIUM
At 300 K, the vapour pressure of a solution containing 1 mole of n -hexane and 3 moles of n -heptane is 550 mm of Hg. At the same temperature, if one more mole of n -heptane is added to this solution, the vapour pressure of the solution increases by 10 mm of Hg. What is the vapour pressure in mmHg of n - heptane in its pure state______?
HARD

Benzene and toluene form an ideal solution over the entire range of composition. The vapour pressure of pure benzene and toluene at T K are 50 mmHg and 40 mmHg, respectively. What is the mole fraction of toluene in vapour phase when 117 g of benzene is mixed with 46 g of toluene?

(Molar mass of benzene and toluene are 78 and 92 g mol-1, respectively)

HARD
The plot of total vapour pressure as a function of mole fraction of the components of an ideal solution formed by mixing liquids X and Y is
HARD
The vapour pressures of chloroform CHCl3, dichloromethane CH2Cl2 at 298 K are 200 mmHg and 415 mmHg, respectively. An ideal solution is prepared by mixing 59.75 g of CHCl3 and 21.25 g of CH2Cl2, the mole fractions of chloroform and dichloromethane in vapour phase, respectively are
MEDIUM
The vapour pressures of pure liquids A and Bare 400 and 600 mm Hg respectively at 298 K. On mixing the two liquids, the sum of their volumes is equal to the volume of the final mixture. The mole fraction of liquid B is 0.5 in the mixture. The vapour pressure of the final solution, the mole fractions of components A and B in the vapour phase, respectively are 
MEDIUM
A mixture of toluene and benzene boils at 100oC . Assuming ideal behaviour, the mole fraction of toluene in the mixture is closest to [Vapour pressures of pure toluene and pure benzene at 100oC are 0.742 and 1.800 bar respectively. 1 atm =1.013  bar]
HARD
Liquids A and B form ideal solution over the entire range of composition. At temperature T, equimolar binary solution of liquids A and B has vapour pressure 45 Torr . At the same temperature, a new solution of A and B having mole fractions xA and xB, respectively, has vapour pressure of 22.5 Torr. The value of xAxB, in the new solution is ____.

(Given that the vapour pressure of pure liquid A is 20 Torr at temperature T)