Name: Elevation in Boiling Point
Uploaded: 2019-07-19
Duration: 7 min 28 s
Description: The boiling point of a liquid is the temperature at which its vapour pressure becomes equal to atmospheric pressure. Let’s learn about the elevation in boili...

Question

200 {cm}^{3}

of aqueous solution of protein contains

1.26 g

of protein. The osmotic pressure of such a solution at

300 K

is found to be

2.57 \times 10^{- 3} atm

. Calculate the molar mass of protein.

Accepted Answer

Volume of the solution $= 200 {cm}^{3} = 200 mL = 0.200 L$

Mass of the protein $= 1.26 g$

Molar mass of protein $= M$

Temperature of the solution, $T = 300 K$

The osmotic pressure, $π = 2.57 \times 10^{- 3} atm$

The pressure that would have to be applied to a pure solvent to prevent it from passing into a given solution by osmosis, often used to express the concentration of the solution.

$π = CRT π = \frac{moles}{volume} RT 2.57 \times 10^{- 3} atm = \frac{moles}{0.200 L} \times 0.0821 atmL / mol K \times 300 K Moles = 2.086 \times 10^{- 5} moles 2.086 \times 10^{- 5} moles = \frac{1.26 g}{M} M = 60402.68 g / mol$

$200 {cm}^{3}$ of aqueous solution of protein contains $1.26 g$ of protein. The osmotic pressure of such a solution at $300 K$ is found to be $2.57 \times 10^{- 3} atm$ . Calculate the molar mass of protein.

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200 cm3 of aqueous solution of protein contains 1.26 g of protein. The osmotic pressure of such a solution at 300 K is found to be 2.57×10-3 atm. Calculate the molar mass of protein.