HARD
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A ball of radius R carries a positive charge whose volume density depends only on the separation r from the ball’s centre as ρ=ρ0 1  rR, where ρ0 is a constant. Assuming the permittivity of the ball and the environment to be equal to unity, find :

(i) The magnitude of the electric field strength as a function of the distance r both inside and outside the ball;

(ii) The maximum intensity Emax and the corresponding distance rm.

Important Questions on Electric Charges and Fields

EASY
The number of electric lines that emerge from a finite charge +q is _____
HARD
In finding the electric field using Gauss law the formula E=qencε0A is applicable. In the formula ε0 is permittivity of free space, A is the area of Gaussian surface and qenc is charge enclosed by the Gaussian surface. This equation can be used in which of the following situation?
EASY
Consider the force F on a charge 'q' due to a uniformly charged spherical shell of radius R carrying charge Q distributed uniformly over it. Which one of the following statements is true for F, if  'q' is placed at distance r from the centre of the shell?
EASY
A charge q is placed at the centre of a cube. The electric flux passing through the cube is
EASY
Shown in the figure are two point charges +Q and -Q inside the cavity of a spherical shell. The charges are kept near the surface of the cavity on opposite sides of the centre of the shell. If σ1 is the surface charge on the inner surface and Q1 net charge on it and σ2 the surface charge on the outer surface and Q2 net charge on it then:

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MEDIUM

Consider a region in free space bounded by the surfaces of an imaginary cube having sides of length a as shown in the figure. A charge +Q is placed at the centre O of the cube. P is such a point outside the cube that the line OPperpendicularly intersects the surface ABCD at R and also OR=RP=a/2. A charge +Q is placed at point P also. What is the total electric flux through the five faces of the cube other than ABCD?

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EASY
The electric flux (in SI units) through any face of a cube due to a positive charge Q situated at the centre of a cube is
EASY

What is the electric flux for Gaussian surface A that encloses the charged particles in free space? [Given: q1=-14 nC,q2=78.85 nC,q3=-56 nC

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EASY
If some charge is given to a solid metallic sphere, the field inside remains zero and by Gauss's law all the charge resides on the surface. Suppose now that Colomb's force between two charges varies as 1r3. Then, for a charged solid metallic sphere
HARD
The region between two concentric spheres of radii 'a' and 'b', respectively (see figure), has volume charge density ρ=Ar , where A is a constant and r is the distance from the centre. At the centre of the spheres is a point charge Q. The value of A such that the electric field in the region between the spheres will be constant, is:

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MEDIUM

Given below are two statements
Statement I : An electric dipole is placed at the centre of a hollow sphere. The flux of electric field through the sphere is zero, but the electric field is not zero anywhere in the sphere.

Statement II : If R is the radius of a solid metallic sphere and Q be the total charge on it. The electric field at any point on the spherical surface of radius r<R is zero but the electric flux passing through this closed spherical surface of radius r is not

In the light of the above statements, choose the correct answer from the options given below:

EASY
A charge +q is at a distance L2 above a square of side L. Then what is the flux linked with the surface?
EASY

Arrangement of charges are shown in the figure. Flux linked with the closed surface P and Q respectively are ________ and ________ .

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MEDIUM
Two hollow concentric spheres A and B are enclosing electric charges 2 C and 8 C respectively. If the radius of A is less than that of B, the ratio of electric flux through A to the electric flux through B is
EASY
When a 10 μC charge is enclosed by a closed surface, the flux passing through the surface is ϕ. Now another 10 μC charge is placed inside the closed surface, then the flux passing through the surface is _____
EASY

When a 10 μC charge is enclosed by a closed surface, the flux passing through the surface is ϕ. Now another charge -5μC is placed inside the same closed surface, then the flux passing through the surface is _____.

 

MEDIUM
If the electric flux entering and leaving an enclosed surface respectively are ϕ1 and ϕ2. then the electric charge inside the surface will be
HARD
The potential (in volts) of a charge distribution is given by

Vz=30-5z2 for z1 m

Vz=35-10 z for z1 m .

Vz does not depend on x and y. If this potential is generated by a constant charge per unit volume ρ0 (in units of ϵ0 ) which is spread over a certain region, then choose the correct statement.
EASY
A charge Q is placed at a distance a2 above the centre of a square surface of side length a. The electric flux through the square surface due to the charge would be?
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HARD
A charged shell of radius R carries a total charge Q. Given Φ as the flux of electric field through a closed cylindrical surface of height h, radius r and with its center same as that of the shell. Here, center of the cylinder is a point on the axis of the cylinder which is equidistant from its top and bottom surfaces. Which of the following option(s) is/are correct? [ 0 is the permittivity of free space]