A body is sliding down an inclined plane (angle of inclination $45°$). If the coefficient of friction is $0.5$ and $g=9.8 \mathrm{m} {\mathrm{s}}^{-2}$ then the downward acceleration of the body in $\mathrm{m} {\mathrm{s}}^{-2}$ is:-

A block of mass m lying on a rough horizontal plane is acted upon by a horizontal force P and another force Q inclined at an angle $\mathrm{\theta }$ to the vertical. The block will remain in equilibrium if the coefficient of friction between it and the surface is :-

Adjoining figure shows two blocks A and B pushed against the wall with a force F. The wall is smooth but the surfaces in contact of A and B are rough. Which of the following is true for the system of blocks to be at rest against the wall ?

The system shown in the figure is in equilibrium. The maximum value of W, so that the maximum value of static frictional force on 100 kg body is 450 N, will be :-

In the arrangement coefficient of friction between the two blocks is µ = $\frac{1}{2}$. The force of friction acting between the two blocks is :-

The coefficient of static friction, µ_s, between block A of mass 2 kg and the table as shown in the figure is 0.2. What would be the maximum mass value of block B so that the two blocks do not move ? The string and the pulley are assumed to be smooth and massless. (g = 10 m/s²)

A horizontal force of $10 \mathrm{N}$ is necessary to just hold a block stationary against a wall. The coefficient of friction between the block and wall is $0.2$. The weight of the block is :-