A conducting rod of length $L$ is rotating with uniform angular velocity $\omega$ in magnetic field $B$ in such a way that the plane of rotation is perpendicular to the magnetic field then finds out induced emf between its ends?

A coil of $50$ turns  and area $0.2 {\mathrm{m}}^2$ in placed perpendicular to a $0.6 \mathrm{T}$ magnetic field the resistance of circuit of coil is $10 \mathrm{\Omega }$ then find out induced charges -

(a) When coil rotates by $180°$

(b) Coil is pulled out of magnetic field.

The figure shows a conducting circular loop of radius $a$  placed in a uniform, perpendicular magnetic field $B$ . A thick metal rod $OA$  is pivoted at the center $O$. The other end of the rod touches the loop at $A$ . The center $O$  and a $C$ fixed point on the loop are connected by a wire $OC$ of resistance $R$. A force is applied at the middle point of the rod $OA$ perpendicularly, so that the rod rotates clockwise at a uniform angular velocity $\omega$. Find the force.

Define induced current and induced charge in electromagnetic induction and obtain the relation,

${\mathrm{Q}}_{\mathrm{induced}}=\frac{\mathrm{N}}{\mathrm{R}}(\mathrm{change} \mathrm{in} \mathrm{magnetic} \mathrm{flux})$

where $\mathrm{N}\to$number of turns in coil

$\mathrm{R}\to$ resistance