A constant magnetic field of $1 \mathrm{T}$ is applied in the $\mathrm{x}>0$ region. A metallic circular ring of radius $1 \mathrm{m}$ is moving with a constant velocity of $1 \mathrm{m} {\mathrm{s}}^{-1}$ along the $x$-axis. At $t=0 \mathrm{s}$, the centre $\mathrm{O}$ of the ring is at $\mathrm{x}=-1 \mathrm{m}$. What will be the value of the induced emf in the ring at $\mathrm{t}=1 \mathrm{s}$ ? (Assume the velocity of the ring does not change.)

For the given circuit the current $i$ through the battery when the key in closed and the steady state has been reached is

A square loop of side $20 \mathrm{cm}$ and resistance $1 \mathrm{\Omega }$ is moved towards right with a constant speed $v_0.$ The right arm of the loop is in a uniform magnetic field of $5 \mathrm{T}.$ The field is perpendicular to the plane of the loop and is going into it. The loop is connected to a network of resistors each of value $4\mathrm{\Omega }.$ What should be the value of $v_0$ so that a steady current of $2 \mathrm{mA}$ flows in the loop ?

The arm $PQ$ of a rectangular conductor is moving from $x=0$ to $x=2b$ outwards and then inwards from $x=2b$ to $x=0$ as shown in the figure. A uniform magnetic field perpendicular to the plane is acting from $x=0$ to $x=b.$ Identify the graph showing the variation of different quantities with distance: