A galvanometer has a current sensitivity of $5$ divisions per milliampere and voltage sensitivity of $1$ division per millivolt. The galvanometer has $30$ divisions and it is to be used as an ammeter to read $6 \mathrm{A}$. This requires a shunt of value

If a shunt of ${\left(\frac{1}{10}\right)}^{\text{th }}$ of the coil resistance is applied to a moving coil galvanometer, then its sensitivity becomes

In an ammeter, $4 \%$ of the main current is passing through the galvanometer. If shunt resistance is $5 \Omega,$ then resistance of galvanometer will be

Assertion: In a shunted galvanometer, only $10 \%$ current passes through the galvanometer. The resistance of the galvanometer is $G$. Then the resistance of the shunt is $\frac{G}{9}$.

Reason: If $\mathrm{S}$ is the resistance of the shunt, then voltage across $S$ and $G$ is same.

The resistance of an ideal ammeter is 

Assertion: Higher the range, greater is the resistance of ammeter.

Reason: To increase the range of ammeter, additional shunt needs to be used across it. 

In an ammeter $0.2 \%$ of main current passes through the galvanometer. If resistance of galvanometer is $G,$ the resistance of ammeter will be 

The resistance of a galvanometer is $90 \mathrm{ohm}$ . If only $10\%$ of the main current may flow through the galvanometer, in which way and of what value, a resistor is to be used?