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A layered sequence for an $F C C = C C P$ metal is shown below :

A face diagonal passes through the centre of atom 4 and the centre (s) of which other atom (s)?

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Important Questions on The Solid State

HARD

Chemistry>Physical Chemistry>The Solid State>Number of Atoms in a Unit Cell

The CORRECT statement(s) for cubic close packed (ccp) three dimensional structure is (are)

MEDIUM

Chemistry>Physical Chemistry>The Solid State>Number of Atoms in a Unit Cell

A compound is formed by atoms

{}^{'}A^{'}

and

{}^{'}B^{'}

B

atoms form

ccp

arrangement. If

A

occupy

\frac{1}{3}

of tetrahedral voids, what is the formula of the compound?

EASY

Chemistry>Physical Chemistry>The Solid State>Number of Atoms in a Unit Cell

In the face centred cubic lattice structure of gold the closest distance between gold atoms is (

{}^{'}a^{'}

being the edge length of the cubic unit cell)

HARD

Chemistry>Physical Chemistry>The Solid State>Number of Atoms in a Unit Cell

A compound is formed by two elements

M

and

N .

Element

N

forms hexagonal closed pack array with

2 / 3

of the octahedral holes occupied by

M .

The formula of the compound is:

EASY

Chemistry>Physical Chemistry>The Solid State>Number of Atoms in a Unit Cell

Element

B

forms ccp structure and

A

occupies half of the octahedral voids, while oxygen atoms occupy all the tetrahedral voids. The structure of bimetallic oxide is:

MEDIUM

Chemistry>Physical Chemistry>The Solid State>Number of Atoms in a Unit Cell

A crystalline solid has

A

-ions at the corners and face centres where as

B^{+}

ions are at the body centre and edge centres of the unit cell. The sim ple formula of the compound will be

MEDIUM

Chemistry>Physical Chemistry>The Solid State>Number of Atoms in a Unit Cell

A compound is formed from elements

X

and

Y

. The atoms of

Y

(anions) form a

ccp

lattice. The atoms of

X

(cations) occupy half of the octahedral voids and half of tetrahedral voids. What is the formula of the compound?

EASY

Chemistry>Physical Chemistry>The Solid State>Number of Atoms in a Unit Cell

A compound made up of atoms of

Y

(anions) forming a CCP arrangement, where the element

X

(cation) occupies octahedral voids. The formula of the compound is

MEDIUM

Chemistry>Physical Chemistry>The Solid State>Number of Atoms in a Unit Cell

The ratio of number of atoms present in a simple cubic, body centered cubic and face centered cubic structure are, respectively :

MEDIUM

Chemistry>Physical Chemistry>The Solid State>Number of Atoms in a Unit Cell

How many total constituent particles are present in simple cubic unit cell?

MEDIUM

Chemistry>Physical Chemistry>The Solid State>Number of Atoms in a Unit Cell

P

atoms occupy the corners of an f.c.c. unit cell and

Q

atoms occupy the face-centered positions, and atoms are not present in two corners of each unit cell. The formula of the compound is

EASY

Chemistry>Physical Chemistry>The Solid State>Number of Atoms in a Unit Cell

In a cubic close packed structure, fractional contributions of an atom at the corner and at the face in the unit cell are, respectively -

MEDIUM

Chemistry>Physical Chemistry>The Solid State>Number of Atoms in a Unit Cell

In chrysoberyl, a compound containing Beryllium, Aluminium and oxygen, oxide ions form cubic close packed structure. Aluminium ions occupy

\frac{1}{4} th

of tetrahedral voids and beryllium ions occupy

\frac{1}{4} th

of octahedral voids. The formula of the compound is

EASY

Chemistry>Physical Chemistry>The Solid State>Number of Atoms in a Unit Cell

An ionic compound has a unit cell constituting of

A

ions at the corners of a cube and

B

ions on the centres of the faces of the cube. The empirical formula for the compound would be

HARD

Chemistry>Physical Chemistry>The Solid State>Number of Atoms in a Unit Cell

In a cubic-close packed structure containing

X, Y

and

Z

atoms, if

Z

occupies all the face centres, $\mathrm{X}$ occupies all the corners and

Y

occupies the body centre of the cube, what is the formula of this compound?

HARD

Chemistry>Physical Chemistry>The Solid State>Number of Atoms in a Unit Cell

How is body centered cubic cell (b.c.c) formed? Calculate the number of atoms in its unit cell.

EASY

Chemistry>Physical Chemistry>The Solid State>Number of Atoms in a Unit Cell

The cubic unit cell of a metal (molar mass

= 63.55 g {mol}^{- 1}

) has an edge length of

362 pm

. Its density is

8.92 {gcm}^{- 3}

. The type of unit cell is

MEDIUM

Chemistry>Physical Chemistry>The Solid State>Number of Atoms in a Unit Cell

A compound is formed by elements of

X, Y

and

Z

. Atoms of

Z

(anions) make

FCC

lattice. Atoms of

X

(cations) occupy all the octahedral voids. Atoms of

Y

(cations) occupy

\frac{1}{3} rd

of the tetrahedral voids. The formula of the compound is:

MEDIUM

Chemistry>Physical Chemistry>The Solid State>Number of Atoms in a Unit Cell

In a face centered cubic lattice atoms A are at the corner points and atoms B at the face centered points. If atom B is missing from one of the face centered points, the formula of the ionic compound is :

MEDIUM

Chemistry>Physical Chemistry>The Solid State>Number of Atoms in a Unit Cell

A mineral consists of a cubic close-packed structure formed by

O^{2 -}

ions where half the octahedral voids are occupied by

A l^{3 +}

and one-eighth of the tetrahedral voids are occupied by

M n^{2 +}

. The chemical formula of the mineral is

A layered sequence for an FCC=CCP metal is shown below : A face diagonal passes through the centre of atom 4 and the centre (s) of which other atom (s)?

Important Questions on The Solid State

Learn and Prepare for any exam you want !

A layered sequence for an $F C C = C C P$ metal is shown below :

A face diagonal passes through the centre of atom 4 and the centre (s) of which other atom (s)?