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A mass M is performing linear simple harmonic motion, then correct graph for acceleration a and corresponding linear velocity v is

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Important Questions on Simple Harmonic Motion

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A particle moves on the X-axis according to the equation, x=x0sin2ωt. The motion is simple harmonic,
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The amplitude of a particle executing SHM with the frequency of 60 Hz is 0.01 m. The maximum value of the acceleration of the particle is
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Velocity at mean position of a particle executing SHM is v. Velocity of the particle at a distance equal to half of the amplitude will be
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A particle is executing SHM of frequency 300 Hz and with amplitude 0.1 cm. Its maximum velocity will be
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The velocity of a particle in SHM at displacement y from the mean position is (a=amplitude, ω=angular frequency).
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The displacement of a particle varies according to the relation x=4(cos πt+sin πt). The amplitude of the particle is

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A particle executes simple harmonic motion between x=-A and x=+A. The time taken for it to go from 0 to A/2 is T1 and to go from A/2 to A is T2. Then
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The x-t graph of a particle undergoing simple harmonic motion is shown below. The acceleration of the particle at t=43 s is

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