The black shapes in the figure below are closed surfaces. The electric field lines are in red. For which case, the net flux through the surfaces is non-zero?

In all cases net flux is non-zero

Let the electrostatic field, E at distance, r from a point charge, q not be an inverse square but instead an inverse cubic, e.g. E = k q r 3 r ^ , here k is a constant. Consider the following two statements: (I) Flux through a spherical surface enclosing the charge is, ϕ = q enclosed ε 0 . (II) A charge placed inside a uniformly charged shell will experience a force. Which of the above statements are valid?

Both statements I and II are invalid

Both statements I and II are valid

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A metallic sphere is kept in between two oppositely charged plates. The most appropriate representation of the field lines is

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Important Questions on Electrostatics

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IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 22 - Electrostatics>KVPY Aptitude Test - Stream SX 2020>Q 1

A proton and an antiproton come close to each other in vacuum such that the distance between them is

10 cm .

Consider the potential energy to be zero at infinity. The velocity at this distance will be:

HARD

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 22 - Electrostatics>KVPY Aptitude Test - Stream SX 2020>Q 2

Consider a sphere of radius

R

with uniform charged density and total charge

Q .

The electrostatic potential distribution inside the sphere is given by

ϕ (r) = \frac{Q}{4 π ε_{0} R} [a + b {(\frac{r}{R})}^{c}] .

Note that the zero of potential is at infinity. The values of

(a, b, c)

are:

HARD

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 22 - Electrostatics>KVPY Aptitude Test - Stream SX 2019>Q 3

A charge

+ q

is distributed over a thin ring of radius

r

with line charge density

λ = \frac{q \sin^{2} θ}{π r}

. Note that the ring is in the

X Y

-plane and

θ

is the angle made by

r

with the

X

-axis. The work done by the electric force in displacing a point charge

+ Q

from the centre of the ring to infinity is

HARD

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 22 - Electrostatics>KVPY Aptitude Test - Stream SX 2018>Q 4

An electrostatic field line leaves at an angle

α

from point charge

q_{1}

and connects with point charge

- q_{2}

at an angle

β

(

q_{1}

and

q_{2}

are positive) see figure below. If

q_{2} = \frac{3}{2} q_{1}

and

α = 30 °,

then

HARD

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 22 - Electrostatics>KVPY Aptitude Test - Stream SX 2018>Q 5

The potential due to an electrostatic charge distribution is

V (r) = \frac{q e^{- α r}}{4 π ε_{0} r},

where

α

is positive. The net charge within a sphere centred at the origin and of radius

1 / α

HARD

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 22 - Electrostatics>KVPY Aptitude Test - Stream SX 2018>Q 6

Two mutually perpendicular infinitely long straight conductors carrying uniformly distributed charges of linear densities $λ_{1}$ and $λ_{2}$ are positioned at a distance $r$ from each other.

Force between the conductors depends on $r$ as

MEDIUM

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 22 - Electrostatics>KVPY Aptitude Test - Stream SX 2016>Q 8

Consider a cube of uniform charge density,

ρ

. The ratio of the electrostatic potential at the center of the cube to that at one of the corners of the cube is,

MEDIUM

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 22 - Electrostatics>KVPY Aptitude Test - Stream SX 2014>Q 11

A certain p-n junction having a depletion region of width

20 μm,

was found to have a breakdown voltage of

100 V

. If the width of the depletion region is reduced to

1 μm

during its production, then it can be used as a zener diode for voltage regulation of:

A metallic sphere is kept in between two oppositely charged plates. The most appropriate representation of the field lines is

Important Questions on Electrostatics

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