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A particle starts SHM from the mean position. Its amplitude is a and total energy E. At one instant its kinetic energy is 3E4. Its displacement at that instant is

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Important Questions on Simple Harmonic Motion

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A particle executes simple harmonic motion with a frequency f. The frequency with which kinetic energy oscillates is

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A particle of mass m is hanging vertically by an ideal spring of force constant k, If mass is made to oscillate vertically, its total energy is:
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A body is moving in a room with a velocity of 20 m s-1 perpendicular to the two walls separated by 5 meters. There is no friction and the collisions with the walls are elastic. The motion of the body is:
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The amplitude of a particle executing SHM is made three-fourth keeping its time period constant. What will be the total energy of the particle in terms of its initial total energy E? (Assume potential energy is zero at the mean position)
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A particle executes SHM with frequency f. The frequency of its kinetic energy is
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When the kinetic energy of a body executing SHM is 13 of the potential energy, the displacement of the body is x percent of the amplitude where x is,
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A body executing SHM passes through its equilibrium. At this instant, it has,
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The total mechanical energy of a spring-mass system in simple harmonic motion is, E=12mω2A2. Suppose the oscillating particle is replaced by another particle of double mass while the amplitude A remains the same. The new mechanical energy will,