MEDIUM
11th ICSE
IMPORTANT
Earn 100

A pipe closed at one end is in resonance of a vibrating tuning fork when the length of the air column is 25 cm. The next resonance occurs when the length of the air column is 77 cm. If the speed of sound in air be 338 ms-1, then calculate the wavelength of the emitted note and the frequency of the fork.

Important Questions on Superposition of Waves-2 : Stationary (Standing) Waves : Vibration of Air Columns

EASY
11th ICSE
IMPORTANT
In a resonance tube, the first and the second resonances are obtained at 22.5 cm and 70.0 cm respectively. Find out the end-correction and the length of the air column for the third resonance.
MEDIUM
11th ICSE
IMPORTANT
 A 25 cm long-closed organ pipe resonates with a tuning fork at 40°C. Determine the frequency of the fork. The speed of sound in air at 0°C is 330 ms-1.
MEDIUM
11th ICSE
IMPORTANT
The length of a pipe open at both ends is 48.8 cm and its fundamental frequency is 320 Hz. Find the radius of the pipe.
If one end of the pipe be closed, what will be the fundamental frequency? (Speed of sound=320 ms-1.)
HARD
11th ICSE
IMPORTANT
The smallest length of a resonance tube closed at one end is 32.0 cm when it is sounded with a tuning fork of frequency 256 Hz and 20.8 cm when sounded with a fork of frequency 384. Calculate the speed of sound and the end-correction.
MEDIUM
11th ICSE
IMPORTANT
A 0.75 cm long closed organ pipe is vibrating in its fundamental mode. If the temperature of the room be 15°C and the speed of sound in air at this temperature be 340 ms-1, then determine the frequency of the note of the pipe. If the temperature rises to 25°C, then what will be the frequency? Consider the effect of temperature on the length of the pipe negligible.