A projectile thrown from a horizontal plane reaches back the plane after covering a total distance of $40 \mathit{\text{m}}$. If the horizontal velocity of the projectile is $10 m{s}^{\mathit{-}\mathit{1}}$,then what is its initial vertical velocity in $\mathrm{m}/\mathrm{s}$ ?Given : $g=10 m{s}^{-2}$

The velocity of a projectile at the initial point $A$ is $\left(2\hat{\mathrm{i}}-3\hat{\mathrm{j}}\right) \mathrm{m} {\mathrm{s}}^{-1}$. Its velocity (in $\mathrm{m} {\mathrm{s}}^{-1}$) at point $B$ is

Two particles are simultaneously projected in the horizontal direction from a point $P$ at a certain height. The initial velocities of the particles are oppositely directed to each other and have magnitude $v$ each. The separation between the particles at a time when their position vectors (drawn from the point $P)$ are mutually perpendicular, is:

A particle starts from origin $\mathrm{O}$ from rest and moves with a uniform acceleration along the positive $x-\mathrm{a}\mathrm{x}\mathrm{i}\mathrm{s}$ . Identify all figures that correctly represent the motion qualitatively.
( $\mathrm{a}=$ acceleration, $v=$ velocity, $x=$ dispalcement, $\mathrm{t}=$ time)
$\left(\mathrm{A}\right)$
$\left(\mathrm{B}\right)$
$\left(\mathrm{C}\right)$
$\left(\mathrm{D}\right)$