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A proton, a deuteron and an alpha particle are accelerated through same potential difference and then they enter a normal uniform magnetic field, the ratio of their kinetic energies will be

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Important Questions on Moving Charges and Magnetism

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CUET (UG)
IMPORTANT
A charged particle enters a magnetic field at right angles to the field. The field exists for a length equal to 1.5 times the radius of circular path of particle. The particle will be deviated from its path by
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CUET (UG)
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A particle of mass m and charge q is incident on XZ plane with velocity v in a direction making angle θ with a uniform magnetic field applied along X -axis. The nature of motion performed by the particle is
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A charged particle enters a uniform magnetic field with velocity vector at an angle of 45o with the magnetic field. The pitch of the helical path followed by the particle is p . The radius of the helix will be
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CUET (UG)
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A charged particle enters a uniform magnetic field with a velocity vector at an angle of 45° with the magnetic field. The pitch of helical path followed by the particle is p . The radius of the helix will be -
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CUET (UG)
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A charged particle is moving in a magnetic field of strength B perpendicular to the direction of the field. If q and m denote the charge and mass of the particle respectively, then the frequency of rotation of the particle is
MEDIUM
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A proton, a deuteron and an α- particle with the same kinetic energy enter a region of uniform magnetic field moving at right angles to B. What is the ratio of the radii of their circular paths?
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CUET (UG)
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A proton of mass 1.67 ×10-27 kg and charge 1.6×10-19 C is projected with a speed of  2×106 m s-1 at an angle of 60° to the x-axis. If a uniform magnetic field of 0.104 T is applied along y-axis, the path of proton is
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Two charged particles M and N  enter a space of uniform magnetic field, with velocities perpendicular to the magnetic field. The paths are as shown in figure. The possible reason (s) is/are?

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