EASY
Earn 100

A series RC circuit with 300 Ω resistance 250 μF capacitance is connected to A.C. supply of 220V, 50 Hz. Find the current in the circuit and potential difference across the resistor and the capacitor.

Important Questions on Alternating Current

EASY
A series LCR circuit with R=43 Ω and L=0.5 H has a leading phase angle of 45° at a frequency of 50 Hz. The capacitance used in the circuit is
HARD
For a series RLC circuit R=XL=2XC. The impedance of the circuit and phase difference between V and I, respectively will be
MEDIUM
A charged capacitor of capacitance C is discharging through a resistor of resistance R. At what time the charge on the capacitor is equal to one half of its initial value?
EASY
An L.C.R. circuit contains resistance of 110 Ω and a supply of 220 V at 300 rad s-1 angular frequency. If only capacitance is removed from the circuit, current lags behind the voltage by 45°. If on the other hand, the only the inductor is removed the current leads by 45° with the applied voltage. The R.M.S. current flowing in the circuit will be:
HARD
750 Hz, 20 Vrms source is connected to a resistance of 100 Ω, an inductance of 0.1803 H and a capacitance of 10 μF all in series. The time in which the resistance (heat capacity  2 J/°C ) will get heated by 10°C. (assume no loss of heat to the surroundings) is close to :
MEDIUM
In a series LCR circuit with an alternating voltage source of frequency f, the current leads the voltage by 45°. The value of c is
EASY
A resistor R, an inductor L, a capacitor C and voltmeters V1,V2 and V3 are connected to an oscillator in the circuit as shown in the adjoining diagram. When the frequency of the oscillation is increased, then at the resonant frequency, the voltmeter reading is zero in the case of
Question Image
MEDIUM
In an LCR series circuit, an inductor 30 mH and a resistor 1 Ω are connected to an AC source of angular frequency 300 rad s-1. The value of capacitance for which the current leads the voltage by 45° is 1x×10-3 F. Then the value of x is
MEDIUM
A seriesLCR  circuit is connected to an ac voltage source. When L is removed from the circuit, the phase difference between current and voltage is π3. If instead C is removed from the circuit, the phase difference is again π3 between current and voltage. The power factor of the circuit is:
MEDIUM
In a series circuit, R=300 Ω, L=0.9 H, C=2.0 μF and  ω=1000 rad s-1. The impedance of the circuit is 
MEDIUM

Match List-I with List-II

  List-i   List-II
a Phase difference between current and voltage in a purely resistive AC circuit i π2; current leads
voltage
b Phase difference between current and
voltage in a pure inductive AC circuit
ii zero
c Phase difference between current and
voltage in a pure capacitive AC circuit
iii π2; current lags
voltage
d Phase difference between current and
voltage in an LCR series circuit
iv tan-1XC-XLR

Choose the most appropriate answer from the options given below :

HARD
A sinusoidal voltage of peak value 283 V and angular frequency 320 s-1 is applied to a series LCR circuit. Given that R=Ω, L=25 mH and C=1000 μF. The total impedance and phase difference between the voltage across the source and the current will respectively be-
MEDIUM
In a series LCR circuit, the inductive reactance XL is 10 Ω and the capacitive reactance XC is 4 Ω. The resistance (R) in the circuit is 6 Ω. The power factor of the circuit is :
HARD

When a 60 mH inductor and a resistor are connected in series with an AC voltage source, the voltage leads the current by 60°. If the inductor is replaced by a 0.5 μF capacitor, the voltage lags behind the current by 30°. What is the frequency of the AC supply?

MEDIUM
For a series LCR circuit with R=100 Ω, L=0.5 mH and C=0.1 pF connected across 220 V-50 Hz AC supply, the phase angle between
current and supplied voltage and the nature of the circuit is:
MEDIUM
A resistance of 5Ω is connected in series with a capacitance of 1mF. The combination is connected to AC source of angular frequency 200rads-1. Then
HARD

A 0.07 H inductor and a 12 Ω resistor are connected in series to a 220 V, 50 Hz AC source. The approximate current in the circuit and the phase angle between current and source voltage are respectively.

[Take π as 227

MEDIUM

A light bulb and an inductor coil are connected to an ac source through a key as shown in the figure below. The key is closed and after sometime an iron rod is inserted into the interior of the inductor. The glow of the light bulb

Question Image

MEDIUM
An arc lamp requires a direct current of 10 A at 80 V to function. If it is connected to a 220 V (rms), 50 Hz AC supply, the series inductor needed for it to work is close to:
EASY
A series R-C circuit is connected to an alternating voltage source. Consider two situations:

i. When capacitor is air filled.

ii. When capacitor is mica filled.

Current through resistor is i and voltage across capacitor is V then: