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A simple pendulum is oscillating with amplitude A and angular frequency ω. At displacement x from the mean position, the ratio of kinetic energy to potential energy is

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Important Questions on Oscillations

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The ratio of kinetic energy to the potential energy of a particle executing SHM at a distance equal to half its amplitude, the distance being measured from its equilibrium position is
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The total energy of the body executing S.H.M. is T.E. Then the kinetic energy when the displacement is half of the amplitude, is
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The ratio of the kinetic energy at mean position to the potential energy at half of the amplitude is
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The displacement of a particle of mass 0.1 kg is, y=0.05sin4π5t+0.4 (where all the quantities are in SI unit). Period of motion is 0.1 s. The total energy of the particle is,
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A particle of mass 0.2 kg moves in simple harmonic motion of amplitude 2 cm. If the total energy of the particle is 4×10-5 J, then the time period of the motion is,
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A simple pendulum of length L swings in a vertical plane. The tension of the string when it makes an angle θ with the vertical and the bob of mass m moves with a speed v is g is the gravitational acceleration
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In a simple pendulum, the period of oscillationT is related to the length of the pendulum l as
 
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A second's pendulum is placed in a space laboratory orbiting around the earth at a height 3R, where R is the radius of the earth. The time period of the pendulum is