All kinds of quadrilaterals can be divided into two triangles of equal area.

Two angles are given, construct an angle such that its measure is equal to the sum of two angles.

Construct the trapezium $\mathrm{PQRS}$ where $\mathrm{PQ}\parallel \mathrm{RS}$ and $\mathrm{PQ}=3.7 \mathrm{cm}, \mathrm{RQ}=3 \mathrm{cm}, \angle \mathrm{P}=129°$ and $\angle \mathrm{Q}=45°$.

Two angles $X$ (obtuse angle) and $Y$ (acute angle) are given. Draw the angles having the following measure.

$X°-Y°$

Construct a trapezium $\mathrm{ABCD}$ in which $\mathrm{AB}\parallel \mathrm{DC}$, $\mathrm{AB}=6.5 \mathrm{cm}$, $\mathrm{CD}=3 \mathrm{cm}$, $\mathrm{AC}=7 \mathrm{cm}$ and $\mathrm{DB}=8.5 \mathrm{cm}$.

Construct the trapezium with the given measures and also find their area.

$BELT$ with $\overline{BE}\parallel \overline{TL}, BE=10 \mathrm{cm}, BT=7 \mathrm{cm}, \angle EBT=85°$ and $\angle BEL=110°$

Construct a trapezium $ABCD$ in which $AD\parallel BC, \angle B=60°, AB=5 \mathrm{cm}, BC=6.2 \mathrm{cm}$ and $CD=4.8 \mathrm{cm}$.