An $\mathrm{AC}$ voltage source of variable angular frequency $\omega$ and fixed amplitude $V_0$ is connected in series with a capacitor $C$ and an electric bulb of resistance $R$ (inductance zero). When $\mathrm{\omega }$ is in increased,

Find the phase-difference between the current and the voltage, If in a series $\mathrm{L}-\mathrm{C}-\mathrm{R}$ circuit, resistance $\mathrm{R}=10 \mathrm{\Omega }$ and the impedance $\mathrm{Z}=10 \mathrm{\Omega }$.

In L-C-R circuit as shown in figure, both switches are open initially. Now switch ${\mathrm{s}}_1$ and ${\mathrm{s}}_2$ are closed. ($\mathrm{q}$ is charge on the capacitor and $\mathrm{\tau }=\mathrm{RC}$ is capacitance time constant) which of the following statement is correct?

In the given circuit, the $\mathrm{AC}$ source has $\mathrm{\omega }=100$ $\mathrm{rad}/\mathrm{c}$. Considering the inductor and capacitor to be ideal, the correct choice (s) is (are)