EASY
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An engineer claims to have made an engine delivering 10 kW power with fuel consumption of 1 g s-1. The calorific value of the fuel is 2 kcal g-1. The claim of the engineer

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Important Questions on Thermodynamics

EASY
A Carnot engine having an efficiency of 110 is being used as a refrigerator. If the work done on the refrigerator is 10 J, the amount of heat absorbed from the reservoir at a lower temperature is
EASY
A Carnot's engine having an efficiency of 110 as heat engine, is used as a refrigerator. If the work done on the system is 10 J, the amount of energy absorbed from the reservoir at lower temperature is
MEDIUM
A Carnot engine has an efficiency of 16. When the temperature of the sink is reduced by 62  , its efficiency is doubled. The temperatures of the source and the sink are, respectively,
MEDIUM
A reservoir is at 827 °C and Carnot's engine takes a thousand kilocalorie of heat from it and exhausts it to a sink at 27 °C. What is the amount of work and the efficiency of the engine?
EASY
Two carnot engines A and B are operated in series. The first one, A, receives heat at T1=600K and rejects to a reservoir at temperature T2. The second engine B receives heat rejected by the first engine and, in turn, rejects to a heat reservoir at T3=400K. Calculate the temperature T2 if the work outputs of the two engines are equal:
EASY
The efficiency of a Carnot engine depends upon
MEDIUM
A Carnot freezer takes heat from water at 0oC inside it and rejects it to the room at a temperature of 27oC. The latent heat of ice is 336×103 Jkg-1. If 5kg of water at 0oC is converted into ice at 0oC by the freezer, then the energy consumed by the freezer is close to :
MEDIUM
Heat is flowing from a refrigerator whose inside temperature is 280 K, to a room at 300 K. Then the amount of heat delivered to the room for each joule of electrical energy consumed in joules is
EASY
The coefficient of performance of a refrigerator is 5. If the temperature inside the freezer is -20 °C, the temperature of the surrounding to which it rejects heat is:
EASY
A Carnot engine, having an efficiency of η=110 as heat engine, is used as a refrigerator. If the work done on the system is 10 J, the amount of energy absorbed from the reservoir at a lower temperature is:
MEDIUM

Helium gas goes through a cycle ABCDA (consisting of two isochoric and two isobaric lines) as shown in figure. The efficiency of this cycle is approximately

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EASY
A refrigerator works between 4C and 30oC. It is required to remove 600 calories of heat every second in order to keep the temperature of the refrigerated space constant. The power required is:

(Take 1 cal = 4.2 Joules)
EASY
Two carnot engines A and B are connected in series in such a way that the work outputs are equal when the temperatures of hot and cold reservoirs of A are 800 K and T, and of engine B are T and 300 K, respectively. Then the temperature T is
MEDIUM
A heat engine is involved with exchange of heat of 1915 J, 40 J, +125 J and Q J, during one cycle achieving and efficiency of 50.0%. The value of Q is:  
EASY
The efficiency of carnot engine is η when its hot and cold reservoirs are maintained at temperature T1 and T2, respectively. To increase the efficiency to 1.5 η, the increase in temperature ΔT of the hot reservoir by keeping the cold one constant at T2 is
MEDIUM
A Carnot engine of efficiency 40 %, takes heat from a source maintained at a temperature of 500 K. It is desired to have an engine of efficiency 60 %. Then, the source temperature for the same sink temperature must be
MEDIUM
Freezing compartment of a refrigerator is at 0°C and room temperature is 27.3°C. Work done by the refrigerator to freeze 1 g of water at 0°C is Lice=80 cal g-1
EASY
The temperature inside a refrigerator is t2 oC and the room temperature is t1 oC. The amount of heat delivered to the room for each joule of electrical energy consumed ideally will be
MEDIUM
Three Carnot engines operate in series between a heat source at a temperature T1 and a heat sink at temperature T4 (see figure). There are two other reservoirs at temperature T2 and T3, as shown, with T1>T2>T3>T4. The three engines are equally efficient if:

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HARD
A solid body of constant heat capacity 1 J -1 is being heated by keeping it in contact with reservoirs in two ways: (i) Sequentially keeping in contact with 2 reservoirs such that each reservoir supplies the same amount of heat. (ii) Sequentially keeping in contact with 8 reservoirs such that each reservoir supplies the same amount of heat. In both, cases the body is brought from initial temperature 100 K to final temperature 200 K . Entropy change of the body in the two cases respectively is: Note: This question was awarded as a bonus since temperatures were given in centigrade instead of in Kelvin. Proper corrections are made in the question to avoid it.