An ester (I) with molecular formula ${\mathrm{C}}_9{\mathrm{H}}_{10}{\mathrm{O}}_2$ was treated with excess of ${\mathrm{CH}}_3\mathrm{MgBr}$ and the compound so formed was treated with ${\mathrm{H}}_2{\mathrm{SO}}_4$ to give an olefin (II). Ozonolysis of (II) gave a ketone with molecular formula ${\mathrm{C}}_8{\mathrm{H}}_8\mathrm{O}$ which show positive iodoform test. The structure of (I) is:

Aspartame, an artificial sweetening agent, has the following structure

On hydrolysis with dilute $\mathrm{HCl}$, it will give

The reason for greater reactivity of acetyl chloride for the nucleophilic substitution than methyl chloride is due to:

$\left(\mathrm{i}\right)$ Capability of oxygen to acquire electrons.
$\left(\mathrm{ii}\right)$ Difference in the nature of carbon of the intermediate tetrahedral in case of acetyl chloride and a pentavalent in case of methyl chloride.
$\left(\mathrm{iii}\right)$ Difference in attack of nucleophile on the compound.

$\left(\mathrm{iv}\right)$ Better leavability of $-\mathrm{COCl}$ than $-\mathrm{Cl}$.

Consider the following statements for hydrolysis reaction:

is more reactive than ${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{COOC}}_2{\mathrm{H}}_5$

 is more reactive than 

 is more reactive than  

Of these the correct statements are$:-$