An exterior angle of a triangle is $105°$ and its two interior opposite angles are equal. Each of these equal angle is

In the adjoining figure, $AB\parallel CD$ and $AB\parallel EF$. The value of $x$ is

In the adjoining figure, the measure of $\angle AED$ is 

All linear pairs are supplementary angles whereas all supplementary angles are not linear pairs.

Two adjacent angles are equal. Is it necessary that each of these angles will be a right angle? Justify your answer.

In the adjoining figure, $OQ$ bisects $\angle AOB$. $OP$ is a ray opposite to ray $OQ$. Prove that $\angle POA=\angle POB$.

In figure given below, ray $OC$ stands on line $AB$ and $4x-3y=20$. Find the measures of $\angle BOC$ and $\angle AOC$.

In figure given below, lines $AB$ and $CD$ intersect each other at the point $O$. If $\angle AOC=45°$, find the values of $x,y \text{and} z$.