An organ pipe $P_{1},$ closed at one end vibrating in its first overtone and another pipe $P_2$, open at both ends vibrating in its third overtone are in resonance with a given tuning fork. The ratio of lengths of $P_1$ and $P_2$ is 

First overtone frequency of a closed pipe of length $l_{1}$ is equal to the $2^{\text {nd }}$ harmonic frequency of an open pipe of length $l_{2}$. The ratio $\frac{l_{1}}{l_{2}}$ is,

An organ pipe closed at one end and another open at both ends will resonate with each other in their fundamental mode of vibration, if their lengths are in the ratio 

Fifth overtone of closed organ pipe is in unision with fifth overtone of open organ pipe. The ratio of their lengths is,

What is the base frequency, if a pipe gives notes of frequencies $255$, $425$ and $595$ Hertz and decide whether it is closed at one end or open at both ends?

When open pipe is closed from one end then third overtone of closed pipe is higher in frequency by $150 \mathrm{Hz}$ than second overtone of open pipe. The fundamental frequency of open end pipe will be

A closed organ pipe and an open organ pipe of the same length produce $2 \mathrm{beats} \mathrm{per} \mathrm{second}$ while vibrating in their fundamental modes. The length of the open organ pipe is halved and that of the closed pipe is doubled. Then, the number of beats produced per second while vibrating in the fundamental mode is

An open pipe of length $L$ vibrates in its fundamental mode. The pressure variation is maximum

If length of a closed organ pipe is $1  \mathrm{m}$ and velocity of sound is $330 \mathrm{m} {\mathrm{s}}^{-1},$ then the frequency of $1^{\text {st }}$ overtone is