
Assertion: In a process if initial volume is equal to the final volume, work done by the gas is zero.
Reason: In an isochoric process work done by the gas is zero.

Important Questions on Heat and Thermodynamics
In a thermodynamics process on an ideal monatomic gas, the infinitesimal heat absorbed by the gas is given by where is temperature of the system and is the infinitesimal change in a thermodynamic quantity of the system. For a mole of monatomic ideal gas Here, is gas constant, is volume of gas, and are constants.
The List-I below gives some quantities involved in a process and List-II gives some possible values of these quantities.
List I | List II | ||
---|---|---|---|
(I) | Work done by the system in process | (P) | |
(II) | Change in internal energy in process | (Q) | |
(III) | Heat absorbed by the system in process | (R) | |
(IV) | Heat absorbed by the system in process | (S) | |
(T) | |||
(U) |
If the process carried out on one mole of monatomic ideal gas is as shown in figure in the - -diagram with the correct match is,



In a thermodynamics process on an ideal monatomic gas, the infinitesimal heat absorbed by the gas is given by where is temperature of the system and is the infinitesimal change in a thermodynamic quantity of the system. For a mole of monatomic ideal gas Here, is gas constant, is volume of gas, and are constants.
The List-I below gives some quantities involved in a process and List-II gives some possible values of these quantities.
Column - I | Column - II | ||
(I) | Work done by the system in process | (P) | |
(II) | Change in internal energy in process | (Q) | |
(III) | Heat absorbed by the system in process | (R) | |
(IV) | Heat absorbed by the system in process | (S) | |
(T) | |||
(U) |
If the process on one mole of monatomic ideal gas is as shown in the -diagram with the correct match is



One mole of diatomic ideal gas undergoes a cyclic process ABC as shown in figure. The process BC is adiabatic. The temperatures at A, B and C are 400 K, 800 K and 600 K respectively. Choose the correct statement :

A gas at state changes to state through path and shown in figure. The change in internal energy is and , respectively. Then



An ideal gas is taken reversibly around the cycle as shown on the T (temperature) - S (entropy) diagram
The most appropriate representation of above cycle on a U (internal energy)-V (volume) diagram is


[ universal gas constant ]



A thermodynamic system undergoes a cyclic process as shown in the diagram. The work done by the system per cycle is


The temperature of of an ideal diatomic gas is increased by without changing the pressure of the gas. The molecules in the gas rotate but do not oscillate. If the ratio of change in internal energy of the gas to the amount of workdone by the gas is Then the value of (round off to the nearest integer) is
Given





