MEDIUM
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Assertion: The specific heat at constant pressure is greater than the specific heat at constant volume i.e., CP > CV .

Reason: In case of specific heat at constant volume, the whole of heat supplied is used to raise the temperature of one mole of the gas through 1°C while in case of specific of heat at constant pressure, heat is to be supplied not only for heating 1 mole of gas through 1°C but also for doing work during expansion of the gas.

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Important Questions on Thermodynamics

MEDIUM
Consider two ideal diatomic gases A and B at some temperature T . Molecules of the gas A are rigid, and have a mass m . Molecules of the gas B have an additional vibrational mode and have a mass m4 . The ratio of the specific heats CV Aand  CVB of gas A and B, respectively is:
HARD
The specific heats, Cp and Cv of a gas of diatomic molecules, A, are given (in units of J mol-1 K-1 ) by 29 and 22, respectively. Another gas of diatomic molecules, B, has the corresponding values 30 and 21. If they are treated as ideal gases, then:
MEDIUM
Two moles of an ideal gas, with CPCV=53, are mixed with three moles of another ideal gas CPCV=43. The value of CPCV for the mixture is
MEDIUM

What will be the molar specific heat at constant volume of an ideal gas consisting of rigid diatomic molecules?

EASY
For a rigid diatomic molecule, the universal gas constant R=nCP, where, CP is the molar specific heat at constant pressure and n is a number. Hence, n is equal to
EASY
The values of Cp and Cv for a diatomic gas are respectively (R=g a s constant)
HARD
Consider a mixture of n moles of helium gas and 2n moles of oxygen gas (molecules taken to be rigid) as an ideal gas. Its CPCV value will be:
MEDIUM
The correct relation between the degrees of freedom f and the ratio of specific heat γ is:
EASY
An ideal gas has molecules with 5 degrees of freedom. The ratio of specific heats at constant pressure Cp and at constant volume CV is:
MEDIUM
When heat Q is supplied to a diatomic gas of rigid molecules, at constant volume its temperature increases by  T . The heat required to produce the same change in temperature, at a constant pressure is:
MEDIUM
One mole of a monoatomic ideal gas undergoes a quasistatic process, which is depicted by a straight line joining points V0,T0 and 2V0,3T0 in a V-T diagram. What is the value of the heat capacity of the gas at the point V0,T0?
MEDIUM
For a diatomic ideal gas in a closed system, which of the following plots does not correctly describe the relation between various thermodynamic quantities?
HARD
One gram mole of an ideal gas A with the ratio of constant pressure and constant volume specific heats γA=53 is mixed with n gram moles of another ideal gas B with γB=75. If the γ for the mixture is 1913, then what will be the value of n?
EASY
One mole of O2 gas is heated at constant pressure starting at 27°C. How much energy must be added to the gas as heat to double its volume?
EASY
The ratio of CpCv for a diatomic gas is
EASY
For a gas CP-CV=R in a state P and CP-CV=1.10R in a state Q,TP and TQ are the temperatures in two different states P and Q, respectively. Then
MEDIUM

Two different metal bodies A and B of equal mass are heated at a uniform rate under similar conditions. The variation of temperature of the bodies is graphically represented as shown in the figure. The ratio of specific heat capacities is:

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MEDIUM
A cylinder with fixed capacity of 67.2 litre contains helium gas at STP. The amount of heat needed to raise the temperature of the gas by 20°C is:
[Given that R=8.31 J mol-1 K-1]
EASY
Cp-Cv=RM and Cv are specific heats at constant pressure and constant volume respectively. It is observed that, Cp-Cv=a for hydrogen gas and Cp-Cv=b for nitrogen gas. The correct relation between a and b is:
EASY
4.0g of a gas occupies 22.4 liters at NTP. The specific heat capacity of the gas at constant volume is 5.0 J K-1 mol-1 . If the speed of sound in this gas at NTP is 952 m s-1 , then the heat capacity at constant pressure is

(Take gas constant R=8.3 J K-1 mol-1 )