The radius of the earth is 6 . 4 × 10 6 m and the mean density is 5 . 5 × 10 3 k g m - 3 . Determine the gravitational potential the earth's surface. ( G = 6 . 67 × 10 - 11 Nm 2 kg - 2 )

The mass of the earth and the gravitational potential at its surface is given by M e = 4 3 πR e 3 ρ . . . . . ( 1 ) V = - GM e R . . . . . ( 2 ) From eqs. (1) and (2) we get, The gravitational potential V = - G R e × 4 3 πR e 3 ρ = 4 3 πGR e 2 ρ = 4 3 × 3 . 14 × ( 6 . 4 × 10 6 ) 2 × 5 . 5 × 10 3 = - 6 . 3 × 10 7 Jkg - 1

E M B I B E

ISC Physics Class XI Part 1>Chapter 15 - Gravitation : Planets and Satellites>NUMERICALS>Q 11

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11th ICSE

IMPORTANT

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At what height above the earth's surface would the acceleration due to gravity be half value on its at the earth's surface? (radius of earth $= 6400 km .$ )

Important Questions on Gravitation : Planets and Satellites

HARD

11th ICSE

IMPORTANT

ISC Physics Class XI Part 1>Chapter 15 - Gravitation : Planets and Satellites>NUMERICALS>Q 11

At what height above the earth's surface would the acceleration due to gravity be one fourth value on its at the earth's surface? (radius of earth

= 6400 km .

)

HARD

11th ICSE

IMPORTANT

ISC Physics Class XI Part 1>Chapter 15 - Gravitation : Planets and Satellites>NUMERICALS>Q 12

At what depth below the surface of the earth the acceleration due to gravity will be one half of the acceleration due to gravity at the surface of the earth? Radius of earth is

6400 km .

HARD

11th ICSE

IMPORTANT

ISC Physics Class XI Part 1>Chapter 15 - Gravitation : Planets and Satellites>NUMERICALS>Q 12

At what depth below the surface of the earth the acceleration due to gravity will be one-fourth of the acceleration due to gravity at the surface of the earth? Radius of earth is