MEDIUM
Earn 100

Calculate the wavelength and energy of radiation emitted for the electronic transition from infinity to stationary state for one H-atom. Given  E1= -13.6 eV .

90.91% studentsanswered this correctly

Important Questions on Structure of Atom

MEDIUM
The first member of the Balmer series of hydrogen atom has a wavelength of 6561 A. The wavelength of the second member of the Balmer series (in nm) is_____________
EASY
The frequency for a series limit of Balmer and Paschen series respectively are f1 and f3. If the frequency of the first line of Balmer series is f2 then the relation between f1, f2 and f3 is
MEDIUM
If the shortest wavelength in Lyman series of hydrogen atom is A, then the longest wavelength in Paschen series of He+ is
MEDIUM
The ratio of the shortest wavelength of two spectral series of hydrogen spectrum is found to be about 9. The spectral series are:
EASY
The value of Planck's constant is 6.63×10-34 Js and the velocity of light is 3.0×108 ms-1. Which value is the closest to the wavelength in nanometers of a quantum of light, with a frequency of 8×1015 s-1?
MEDIUM

For any given series of spectral lines of atomic hydrogen, let  Δv-=v-max-v-min  be the difference in maximum and minimum wave number in cm-1

The ratio Δv-Lyman/Δv-Balmar is

MEDIUM
According to Bohr's theory, the time averaged magnetic field at the centre (i.e., nucleus) of a hydrogen atom due to the motion of electrons in the nth orbit is proportional to: (n= principal quantum number)
HARD
Radiation, with wavelength 6561 Å falls on a metal surface to produce photoelectrons. The electrons are made to enter a uniform magnetic field of 3×10-4 T . If the radius of the largest circular path followed by the electrons is 10 mm , the work function of the metal is close to:
EASY
Given the value of Rydberg constant is 107 m-1, the wave number of the last line of the Balmer series in hydrogen spectrum will be:
MEDIUM
Which of the graphs shown below does not represent the relationship between incident light and the electron ejected from metal surface?
EASY
Calculate the energy in corresponding to light of wavelength 45 nm: (Planck’s constant h=6.63×10-34Js:speed of light c=3×108 ms-1)
EASY
A particular station of All India Radio, New Delhi, broadcasts on a frequency of 1,368 kHz (kilo Hertz). The wavelength of the electromagnetic radiation emitted by the transmitter is [speed of light, c=3.0×108 ms-1]
EASY
When the electron in hydrogen atom jumps from fourth Bohr orbit to second Bohr orbit, one gets the
MEDIUM
Taking the wavelength of first Balmer line in hydrogen spectrum (n=3  to n=2) as 660 nm , the wavelength of the 2nd Balmer line (n = 4  to  n = 2) will be :
EASY
The time period of revolution of electron in its ground state orbit in a hydrogen atom is 1.6×10-16s. The frequency of revolution of the electron in its first excited state (in s-1 ) is:
MEDIUM
For which one of the following, Bohr model is not valid?
HARD
The work function of sodium metal is 4.41×10-19J. If photons of wavelength 300 nm are incident on the metal, the kinetic energy of the ejected electrons will be h=6.63×10-34J s; c=3×108  m s-1__________×10-21J
EASY
In Balmer series for hydrogen atom, find the energy of photon corresponding to longest wavelength.
MEDIUM
Electromagnetic radiation of wavelength 663 nm is just sufficient to ionise the atom of metal A. The ionization energy of metal A in kJ mol-1 is ___. (Rounded-off to the nearest integer) h=6.63×10-34Js,c=3.00×108 ms-1, NA=6.02×1023 mol-1