Carbanions derived from aldehydes/ketones are called enolates, as they represent anions (conjugate bases) of the enol forms. Enol ethers can be prepared and are synthetically important. These anions react with an alkyl halide at the carbon or oxygen atom.

Trimethylsilylchloride $\left({\mathrm{Me}}_3\mathrm{SiCl}\right)$ reacts almost exclusively with enolates. One such reaction is shown below. where ketone $\mathrm{I}$ is treated with LDA. followed by ${\mathrm{Me}}_3\mathrm{SiCl}$ to obtain trimethylsilyl derivative of $\mathrm{I}$. The possible intermediate carbanions ($\mathrm{II}$and $\mathrm{III}$) and the possible products ($\mathrm{IV}$ to $\mathrm{VII}$) are shown. [LDA $=$ lithium diisopropylamide $\left(\mathrm{LiN}{\left({\mathrm{isoC} }_3{\mathrm{H}}_7\right)}_2\right)$, is a strong base but a very poor nucleophile].

The correct order of stability of given carbocation is:

Which of the following carbocations is most stable?

Choose the correct statement regarding the formation of carbocations A and B given :-

The decreasing order of the stability of the following carbocations is

The stability order of the above carbocations is 

Which of the following is most stable$?$

Assertion (A): Tertiary carbocations are more reactive than secondary and primary carbocations.

Reason (R): Hyper conjugation, as well as inductive effect due to additional alkyl groups stabilise tertiary carbocations.

Consider the following carbocations

(a) ${\mathrm{Cl}}_3{\mathrm{C}}^{+}$

(b) ${\mathrm{Cl}}_2{\mathrm{CH}}^{+}$

(c) ${{\mathrm{ClCH}}_2}^{+}$

(d) ${{\mathrm{CH}}_3}^{+}$

The stability sequence follows the order 

Arrange the following carbocations in decreasing order of stability.