HARD
JEE Main
IMPORTANT
Earn 100

Choose the correct representation of conductometric titration of benzoic acid vs sodium hydroxide.

50% studentsanswered this correctly

Important Questions on Electrochemistry

MEDIUM
JEE Main
IMPORTANT

Consider the cell Pt(s)H2( s)(latm)H+aq,H+=1||Fe3+(aq),Fe2+(aq)Pt(s)

Given: EFe3+/Fe2+°=0.771 V and EH+/12H2°=0 V, T=298 K

If the potential of the cell is 0.712 V the ratio of concentration of Fe2+ to Fe3+ is
(Nearest integer)

HARD
JEE Main
IMPORTANT

Pt(s)H2( g)(1bar)H+(aq)(1M)M3+(aq),M+(aq)Pt(s)

The Ecell  for the given cell is 0.1115 V at 298 K

When M+(aq)M3+(aq)=10a

The value of a is ___________

Given : Eθ=M3+/M+0.2 V

2.303RTF=0.059 V

 

EASY
JEE Main
IMPORTANT

Following figure shows dependence of molar conductance of two electrolytes on concentration. Λm0 is the limiting molar conductivity.

Question Image

 

The number of Incorrect statement(s) from the following is _____

(A) Λm0 for electrolyte A is obtained by extrapolation
(B) For electrolyte B,   Λm Vs c  graph is a straight line with intercept equal to Λm0
(C) At infinite dilution, the value of degree of dissociation approach zero for electrolyte B.
(D) Λm for any electrolyte A or B can be calculated using λ° for individual ions.

MEDIUM
JEE Main
IMPORTANT

The equilibrium constant for the reaction Zns+Sn2+aqZn2+aq+Sns is 1×1020 at 298 K. The magnitude of standard electrode potential of Sn/Sn2+ if EZn2*/Zn0=-0.76 V is _____ ×10-2 V. (Nearest integer)

Given : 2.303RTF=0.059 V

MEDIUM
JEE Main
IMPORTANT

Consider the cell

PtsH2g,1atmH+aq,1M|Fe3+aq,Fe2+aqPts

When the potential of the cell is 0.712 V at 298 K, the ratio Fe2+/Fe3+ is
(Nearest integer)
Given: Fe3++e-=Fe2+,E°Fe3+,Fe2+Pt=0.771 2.303RTF=0.06 V

HARD
JEE Main
IMPORTANT

The electrode potential of the following half cell at 298 K

XX2+0.001MY2+0.01MY is _____ ×10-2 V (Nearest integer)

Given : EX2+X0=-2.36 V

EY2+Y0=+0.36 V

2.303RTF=0.06 V

EASY
JEE Main
IMPORTANT

Which one of the following statements is correct for electrolysis of brine solution?

MEDIUM
JEE Main
IMPORTANT

The logarithm of equilibrium constant for the reaction Pd2++4Cl-PdCl42-   is
(Nearest integer)

Given: 2.303RTF=0.06 V

Pd(aq)2++2e-Pd(s)  Eo=0.83 V

PdCl42-(aq)+2e-Pd(s)+4Cl-(aq)

Eo=0.65 V