The value of Δ 0 for Ti H 2 O 6 3 + is found to be 240 kJ mol - 1 , then predict the colour of the complex using the following table. h = 6 × 10 - 34 J - Sec , N A = 6 × 10 23 , c = 3 × 10 8 m sec - 1 Absorbed light λ ( nm ) (absorbed) Colour exhibited Blue 435 - 480 Yellow green-blue 480 - 490 Orange blue-green 490 - 500 Red green 500 - 560 purple yellow-green 560 - 580 violet Yellow 580 - 595 blue Red 605 - 700 blue green

E = h × c × N A λ λ = 6 × 10 - 34 × 3 × 10 8 × 6 × 10 23 240 × 10 3 = 450 nm Therefore, the colour of the complex is Yellow.

Which of the following complexes will show geometrical isomerism?

Aquachlorobis(ethylenediamine)cobalt(II)chloride

Potassium tris(oxalato)chromate(III)

Pentaaquachlorochromium(II)chloride

Potassiumamminetrichloroplatinate(II)

The correct option(s) regarding the complex Co en NH 3 3 H 2 O 3 + is (are) (en = H 2 NCH 2 CH 2 NH 2 )

It absorbs light at longer wavelength as compared to Co en NH 3 4 3 +

The correct statement(s) regarding the binary transition metal carbonyl compounds is (are) (Atomic numbers: F e = 26 , N i = 28 )

Metal - carbon bond strengthens when the oxidation state of the metal is lowered

Total number of valence shell electrons at metal center in Fe CO 5 or Ni CO 4 is 16

The carbonyl C - O bond weakens when the oxidation state of the metal is increased

The correct combination is

NiCl 4 2 - - paramagnetic; Ni ( CO ) 4 - tetrahedral

NiCl 4 2 - - Square planar; Ni ( CN ) 4 2 - - paramagnetic

Ni ( CN ) 4 2 - - tetrahedral; Ni ( CO ) 4 2 - - paramagnetic

NiCl 4 2 - - diamagnetic; Ni ( CO ) 4 - square-planar

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${[Co {({NH}_{3})}_{6}]}^{3 +}$ and ${[{CoF}_{6}]}^{3 -}$ both are complexes of $Co (III),$ but ${[Co {({NH}_{3})}_{6}]}^{3 +}$ is diamagnetic while ${[{CoF}_{6}]}^{3 -}$ is paramagnetic with $μ = 4.90 B . M .$ Explain.

Important Questions on Coordination Compounds

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Alpha Question Bank for Engineering: Chemistry>Chapter 21 - Coordination Compounds>Exercise-1>Q 22

Arrange the following in increasing order as directed.

$(a)$ $(i) [{CoCl}_{3} {({NH}_{3})}_{3}],$ $(ii) [CoCl {({NH}_{3})}_{5}] {Cl}_{2},$ $(iii) [Co {({NH}_{3})}_{6}] {Cl}_{3},$ $(iv) [{CoCl}_{2} {({NH}_{3})}_{4}] Cl$ - Molar conductance

$(b)$ $Br, S^{2 -}, {NO}_{2}^{-}, CO, H_{2} O, {CN}^{-}, {NH}_{3}, {NO}_{3}^{-}$ - Strength of the ligands.

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Alpha Question Bank for Engineering: Chemistry>Chapter 21 - Coordination Compounds>Exercise-1>Q 23

For each of the following complexes, draw a crystal field energy-level diagram, assign the electrons to orbitals, and predict the number of unpaired electrons:

$(a)$ ${[{CrF}_{6}]}^{3 -}$

$(b)$ ${[V {(H_{2} O)}_{6}]}^{3 +}$

$(c)$ ${[Fe (CN)_{6}]}^{3 -}$

$(d)$ ${[Cu (en)_{3}]}^{2 +}$

$(e)$ ${[{FeF}_{6}]}^{3 -}$

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Alpha Question Bank for Engineering: Chemistry>Chapter 21 - Coordination Compounds>Exercise-1>Q 24

Cobalt

(II)

is stable in aqueous solution but in the presence of complexing reagents (strong field ligands) it is readily oxidised. Why?

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Alpha Question Bank for Engineering: Chemistry>Chapter 21 - Coordination Compounds>Exercise-1>Q 25

The value of $Δ_{0}$ for ${[Ti {(H_{2} O)}_{6}]}^{3 +}$ is found to be $240 kJ {mol}^{- 1}$ , then predict the colour of the complex using the following table. $(h = 6 \times 10^{- 34} J - Sec, N_{A} = 6 \times 10^{23}, c = 3 \times 10^{8} m \sec^{- 1})$

Absorbed light	$λ (nm)$ (absorbed)	Colour exhibited
Blue	$435 - 480$	Yellow
green-blue	$480 - 490$	Orange
blue-green	$490 - 500$	Red
green	$500 - 560$	purple
yellow-green	$560 - 580$	violet
Yellow	$580 - 595$	blue
Red	$605 - 700$	blue green

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Alpha Question Bank for Engineering: Chemistry>Chapter 21 - Coordination Compounds>Exercise-1>Q 26

$(a)$ ${[Ti {(H_{2} O)}_{6}]}^{3 +}$ absorbs light of wavelength $5000 Å .$ Name one ligand which would form a titanium $(III)$ complex absorbing light of lower wavelength than $5000 Å$ and one ligand which would form a complex absorbing light of wavelength higher than $5000 Å .$

$(b)$ Calculate the magnetic moments (spin only) of the following complexes

$(i) {[{PtCl}_{6}]}^{2 -}$

$(ii) [Cr (CO)_{6}]$

$(iii) {[lr {({NH}_{3})}_{6}]}^{3 +}$

$(iv) {[Pd (en)_{2}]}^{2 +}$

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Alpha Question Bank for Engineering: Chemistry>Chapter 21 - Coordination Compounds>Exercise-1>Q 27

What type of isomers are the following?

$(i) {[Mn (CO)_{5} SCN]}^{+}$ and ${[Mn (CO)_{5} NCS]}^{+}$

$(ii) [Co (en)_{3}] [Cr (CN)_{6}]$ and $[Cr (en)_{3}] [Co (CN)_{6}]$

$(iii) [Co {({NH}_{3})}_{5} {NO}_{3}] {SO}_{4}$ and $[Co {({NH}_{3})}_{5} {SO}_{4}] {NO}_{3}$

$(iv) [Co {(H_{2} O)}_{2} {Cl}_{2} (py)_{2}] C$ and $[Co (H_{2} O) {Cl}_{3} (py)_{2}] H_{2} O$

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Alpha Question Bank for Engineering: Chemistry>Chapter 21 - Coordination Compounds>Exercise-1>Q 28

(a)

Write all possible constitutional isomers of the compound

Ru {({NH}_{3})}_{5} ({NO}_{2}) Cl .

Label the isomers as linkage isomers or ionization isomers.

(b)

There are six possible isomers for a square planar palladium

(II)

complex that contains two

{NH}_{3}

and two

{SCN}^{-}

ligands. Sketch the structures of all six, and label them according to the classification.

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Alpha Question Bank for Engineering: Chemistry>Chapter 21 - Coordination Compounds>Exercise-1>Q 29

How many geometrical isomers are possible for each of the following complexes?

$(a)$ $[Pt {({NH}_{3})}_{2} (SCN)_{2}]$

$(b)$ ${[{CoCl}_{2} {Br}_{2}]}^{2 -}$ (tetrahedral)

$(c)$ $[Co {({NH}_{3})}_{3} {({NO}_{2})}_{3}]$

$(d)$ $[Pt (en) C [2]$

$(e)$ ${[{CrBr}_{2} (en)_{2}]}^{+}$

$(f)$ ${[Rh (en)_{3}]}^{3 +}$

CoNH363+ and CoF63- both are complexes of Co(III), but CoNH363+is diamagnetic while CoF63- is paramagnetic with μ=4.90 B.M. Explain.

Important Questions on Coordination Compounds

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${[Co {({NH}_{3})}_{6}]}^{3 +}$ and ${[{CoF}_{6}]}^{3 -}$ both are complexes of $Co (III),$ but ${[Co {({NH}_{3})}_{6}]}^{3 +}$ is diamagnetic while ${[{CoF}_{6}]}^{3 -}$ is paramagnetic with $μ = 4.90 B . M .$ Explain.