Question

Compound

A, C_{5} H_{10} O_{5}

, given a tetraacetate with

{AC}_{2} O

and oxidation of

A

with

{Br}_{2} - H_{2} O

gives an acid,

C_{5} H_{10} O_{6}

. Reduction of

A

with

HI

gives isopentane. The possible structure of

A

is :

Accepted Answer

Answer

Answer

Answer

List I	List II
Test	Functional group / Class of Compound
(A) Molisch's Test	(I)Peptide
(B) Biuret Test	(II)Carbohydrate
(C) Carbylamine Test	(III) Primary amine
(D) Schiff's Test	(IV) Aldehyde

Compound $A, C_{5} H_{10} O_{5}$ , given a tetraacetate with ${AC}_{2} O$ and oxidation of $A$ with ${Br}_{2} - H_{2} O$ gives an acid, $C_{5} H_{10} O_{6}$ . Reduction of $A$ with $HI$ gives isopentane. The possible structure of $A$ is :

Important Questions on Biomolecules