The work function for caesium metal is 3 . 31 × 1 . 6 × 10 - 19 Joule . Determine its threshold frequency for it.

Work function ϕ of metal is defined as minimum energy required to cause photoelectric emission from the metal. The energy corresponds to that of a photon with threshold frequency. ϕ = h ν ∘ So, the threshold frequency: ν ∘ = ϕ h = 3 . 31 × 1 . 6 × 10 - 19 J 6 . 63 × 10 - 34 J s = 8 × 10 14 Hz Hence, the threshold frequency is 8 × 10 14 Hz for the given metal.

E M B I B E

Physics Crash Course (Based on Revised Syllabus-2023)>Chapter 10 - Solved Physics Paper-1>Exercise>Q 20

MEDIUM

12th Rajasthan Board

IMPORTANT

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Important Questions on Solved Physics Paper-1

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12th Rajasthan Board

IMPORTANT

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12th Rajasthan Board

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12th Rajasthan Board

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IMPORTANT

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12th Rajasthan Board

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IMPORTANT

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12th Rajasthan Board

IMPORTANT

Physics Crash Course (Based on Revised Syllabus-2023)>Chapter 10 - Solved Physics Paper-1>Exercise>Q 40

The work function for caesium metal is