Draw A B - of length 7.3 c m and find its axis of symmetry.

Axis of symmetry of line segment A B - will be the perpendicular bisector of A B - . So, we need to construct the perpendicular bisector of A B . Steps of construction: (i) Draw a line segment A B - = 7.3 c m using ruler. (ii) With A as the center and radius more than half of A B - , draw arcs above and below the line segment A B - . (iii) With B as the center and radius same as in step (ii), draw arcs above and below the line segment A B - . (iv) Name the point of intersection above the line segment as C and the point of intersection below the line segment as D . (v) Join C and D . Therefore, C D is the axis of symmetry of the line segment A B .

Draw a line l and a point X on it. Through X , draw a line segment X Y - perpendicular to l . Now draw a perpendicular to X Y - at Y . (use ruler and compasses)

Steps of construction: (i) Draw a line ‘ l ’ and mark a point X on it. (ii) Choose any convenient radius and with the pointed end of the compass at X , draw an arc intersecting the line ‘ l ’ at two points A and B . (iii) With A and B as centers and a radius greater than X A , draw two arcs, which intersect at a point, say C . (iv) Join X C and produce it to Y . Therefore, we obtain X Y perpendicular to ‘ l ’. (v) Choose any convenient radius and with the pointed end of the compass at Y , draw an arc intersecting X Y at two points P and Q . (vi) With P and Q as centers and radius greater than Y P , draw two arcs which intersect each other at a point say Z . (vii) Join Y Z . Therefore, we obtain Y Z perpendicular to X Y at Y .

Study the given figure and answer the question. Name the three-line segments.

We have to name three-line segments from the given diagram. In geometry, a line segment is a part of a line that is bounded by two distinct end-points. Hence, the three-line segments are A C ¯ , C B ¯ , A B ¯ .