MEDIUM
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Find out the pH of the solution, given that the equivalent conductance of 0.01 M solution of  a weak acid HA is 19.6 S cm2 eq-1 . The equivalent conductance of the electrolyte at infinite dilution is 392 S cm2 eq-1. 

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Important Questions on Electrochemistry

HARD
mo for NaCl,HCl and NaA are 126.4,425.9 and 100.5Scm2mol-1 respectively. If the conductivity of 0.001MHA is 5×10-5 S cm-1, degree of dissociation of HA is
EASY
Λm0 values for NaCl,HCl and CH3COONa are 126.4 S cm2 mol-1, 425.9 S cm2 mol-1 and 91.0 S cm2 mol-1 respectively. Λm0 value for CH3COOH is
MEDIUM

The molar conductivity of 0.007 M acetic acid is 20 S cm2 mol-1. What is the dissociation constant of acetic acid? Choose the correct option.

λH+=350 S cm2 mol-1λCH3COO-=50 S cm2 mol-1

MEDIUM
Ionic mobility of Ag+ is λAg+=5×10-1 ohm-1 cm2 eq-1
EASY

The limiting molar conductivity and molar conductivity of acetic acid are 390.5 S cm2. mol-1 and 48.15 S cm2. mol-1 respectively. Calculate the degree acid are of dissociation of the weak acid?

EASY

The molar conductance of NaCl, HCl and CH3COONa at infinite dilution are 126.45, 426.16 and 91.0 Scm2 mol-1 respectively. The molar conductance of CH3COOH at infinite dilution is. Choose the right option for your answer.

MEDIUM
0.002M solution of a weak acid has an equivalent conductance (Λ)60ohm-1 cm2eq-1. What will be the pH ? (Given : Λ°=400ohm-1 cm2eq-1 ]
MEDIUM
λ°m for NH4Cl, NaOH and NaCl are 130, 248 and 126. 5 ohm-1em2mo-1 respectively. The λ°m NH4OH will be,
MEDIUM
The molar conductance at infinite dilution for sodium acetate, hydrochloric acid and sodium chloride are 91.0, 426.2 and 126.5 S cm2mol-1 respectively at 298 K. The molar conductance of acetic acid at infinite dilution would be
EASY
If the molar conductivities in S cm2 mol-1 of NaCl, KCl and NaOH  at infinite dilution are 126 and 150 and 250 respectively, the molar conductivity of KOH in S cm2 mol-1 is -
MEDIUM
The solubility 's' of a sparingly soluble salt is related to its equivalent conductance at infinite dilution by the relation (k in specific conductance)
MEDIUM
Given λ°Mg2+=106 S cm2 mole-1, λ°SO42-=160 S cm2 mole-1. The value of λ°MgSO4 (in S cm2 mole-1)  is
MEDIUM
The limiting molar conductivity of weak electrolytes can be calculated by using the law
HARD

Plotting 1/Λm against m for aqueous solutions of a monobasic weak acid (HX) resulted in a straight line with y-axis intercept of P and slope of S. The ratio P/S is
Λm= molar conductivity 

Λmo= limiting molarconductivity   c= molarconcentration

Ka= dissociation constant of HX

EASY

The following table gives the values of limiting molar conductivity λm0 of some ions

Ion λ0S cm2 mol-1
H+ 349.6
SO42- 160.0
Cl-1 76.3
OH- 199.1
Na+ 50.1

Given λm0 (magnesium sulfate) =266 S cm2 mol-1 and λm0 (hydrochloric acid) =425.9 S cm2 mol-1. The value of λm0 for magnesium chloride (in S cm2 mol-1) is

EASY
The specific conductance K of 0.02 M aqueous acetic acid solution at 298 K is 1.65×10-4Scm-1. The degree of dissociation of acetic acid is

[Given: equivalent conductance at infinite dilution of H+=349.1Scm2mol-1 and CH3COO-=40.9Scm2  mol-1 ]