Name: How to Represent Organic Molecules in 3D?
Uploaded: 2019-07-19
Duration: 17 min 15 s
Description: You have seen 3D paintings where an artist paints on paper in such a way that there is a 3D effect. Similarly, there are some methods where we can interpret...

Question

Find out the structures of glucose, vanillin, camphor, and paracetamol. Mark the carbon atoms present in them. Assign the hybridization state to each of the carbon and oxygen atom. Identify sigma

(σ)

and pi

(π)

bonds in these molecules.

Accepted Answer

Glucose is a carbohydrate with the molecular formula $C_{6} H_{12} O_{6}$ . Hybridization is the mixing of atomic orbitals to give new hybrid orbitals with different structures and energy. One $s$ orbital and three $p$ orbitals are mixing to give ${sp}^{3}$ hybridized orbitals, one $s$ orbital, and two $p$ orbitals are mixed to give ${sp}^{2}$ hybridized orbitals, and one $s$ orbital and one $p$ orbitals are mixed to get $sp$ hybridized orbitals.

Hybridization of $C_{1} = {sp}^{2}$ , Hybridization of $C_{2} / C_{3} / C_{4} / C_{5} / C_{6} = {sp}^{3}$ , hybridization of oxygen of $- CHO$ group $= {sp}^{2}$ . Hybridization of oxygen other than $- CHO$ group $= {sp}^{3}$ .

Sigma bonds are chemical covalent bonds that are formed by the axial overlapping of atomic orbitals whereas pi bonds are formed by the sidewise overlapping of atomic orbitals. Every single bond is sigma bonds and in each double bond one is sigma and the other one is pi bond. There are a total of 23 sigma bonds and one pi bond in glucose.

The structure of vanillin is given below. Hybridization is the mixing of atomic orbitals to give new hybrid orbitals with different structures and energy. One $s$ orbital and three $p$ orbitals are mixing to give ${sp}^{3}$ hybridized orbital, one $s$ orbital, and two $p$ orbitals are mixed to give ${sp}^{2}$ hybridized orbital, and one $s$ orbital and one $p$ orbitals are mixed to get $sp$ hybridized orbital.

Vanillin $\Rightarrow$

Hybridization of ring carbon ${sp}^{2}$ , Hybridization of carbon of $(- CHO)$ group $= {sp}^{2}$ , Hybridization of oxygen of $(- {OCH}_{3})$ group $= {sp}^{3}$ , Hybridization of carbon of $(- {OCH}_{3})$ group $= {sp}^{3}$

Sigma bonds are chemical covalent bonds that are formed by the axial overlapping of atomic orbitals whereas pi bonds are formed by the sidewise overlapping of atomic orbitals. Every single bond is sigma bonds and in each double bond one is sigma and the other one is pi bond. There are a total of 19 sigma bonds and 4 pi bonds in vanillin.

The structure of camphor is given below. Hybridization is the mixing of atomic orbitals to give new hybrid orbitals with different structures and energy. One $s$ orbital and three $p$ orbitals are mixing to give ${sp}^{3}$ hybridized orbital, one $s$ orbital, and two $p$ orbitals are mixed to give ${sp}^{2}$ hybridized orbital, and one $s$ orbital and one $p$ orbitals are mixed to get $sp$ hybridized orbital.

Camphor $\Rightarrow$

Hybridisation of $C_{1} / C_{3} / C_{4} / C_{5} / C_{6} / C_{7} = {sp}^{3}$ , hybridisation of $C_{2} = {sp}^{2}$ , Hybridisation of oxygen $= {sp}^{2}$

Sigma bonds are chemical covalent bonds that are formed by the axial overlapping of atomic orbitals whereas pi bonds are formed by the sidewise overlapping of atomic orbitals. Every single bond is sigma bonds and in each double bond one is sigma and the other one is pi bond. There are a total of 28 sigma bonds and 1 pi bond in camphor.

The structure of paracetamol is given below. Hybridization is the mixing of atomic orbitals to give new hybrid orbitals with different structures and energy. One $s$ orbital and three $p$ orbitals are mixing to give ${sp}^{3}$ hybridized orbital, one $s$ orbital, and two $p$ orbitals are mixed to give ${sp}^{2}$ hybridized orbital, and one $s$ orbital and one $p$ orbitals are mixed to get $sp$ hybridized orbital.

Sigma bonds are chemical covalent bonds that are formed by the axial overlapping of atomic orbitals whereas pi bonds are formed by the sidewise overlapping of atomic orbitals. Every single bond is sigma bonds and in each double bond one is sigma and the other one is pi bond. There are a total of 20 sigma bonds and 4 pi bonds in paracetamol.

Find out the structures of glucose, vanillin, camphor, and paracetamol. Mark the carbon atoms present in them. Assign the hybridization state to each of the carbon and oxygen atom. Identify sigma $(σ)$ and pi $(π)$ bonds in these molecules.

Important Questions on Basic Principles of Organic Chemistry

Learn and Prepare for any exam you want !

Find out the structures of glucose, vanillin, camphor, and paracetamol. Mark the carbon atoms present in them. Assign the hybridization state to each of the carbon and oxygen atom. Identify sigmaσ and pi π bonds in these molecules.

Important Questions on Basic Principles of Organic Chemistry

Learn and Prepare for any exam you want !

Find out the structures of glucose, vanillin, camphor, and paracetamol. Mark the carbon atoms present in them. Assign the hybridization state to each of the carbon and oxygen atom. Identify sigma $(σ)$ and pi $(π)$ bonds in these molecules.