EASY
Earn 100

Find the auxiliary circle for parabola x2+4x+4y+16=0.

Important Questions on Parabola

MEDIUM
The focus of the parabola y2-4y-x+3=0 is
HARD
Let P4,-4 and Q9,6 be two points on the parabola, y2=4x and let X be any point on the arc POQ of this parabola, where O is the vertex of this parabola, such that the area of PXQ is maximum. Then this maximum area (in sq. units) is :
HARD
Suppose the parabola (y-k)2=4(x-h), with vertex A, passes through O=(0, 0) and L=(0, 2). Let D be an end point of the latus rectum. Let the y-axis intersect the axis of the parabola at P. Then PDA is equal to
HARD
A chord is drawn through the focus of the parabola y 2 = 6 x  such that its distance from the vertex of this parabola is 5 2 , then its slope can be 
MEDIUM
The focus of the parabola y=2 x 2 +x is
HARD
If y=mx+c is the normal at a point on the parabola y2=8x whose focal distance is 8 units, then c is equal to:
HARD
If PQ be a double ordinate of the parabola, y2=-4x, where P lies in the second quadrant. If R divides PQ in the ratio 2:1, then the locus of R is:
MEDIUM
The equation of the directrix of the parabola x2-4x-3y+10=0 is
MEDIUM
Axis of a parabola lies along x-axis. If its vertex and focus are at distances 2 and 4 respectively from the origin, on the positive x-axis then which of following points does not lie on it?
HARD
Let O be the vertex and Q be any point on the parabola, x2=8y. If the point P divides the line segment OQ internally in the ratio 1:3, then the locus of P is
MEDIUM
The centres of those circles which touch the circle, x2+y2-8x-8y-4=0, externally and also touch the x - axis, lie on
EASY
The parabola having its focus at 3,2 and directrix along the y-axis has its vertex at
HARD
P and Q are two distinct points on the parabola, y2=4x, with parameters t and t1, respectively. If the normal at P passes through Q, then the minimum value of t12 , is
MEDIUM
The focus of the parabola y+12=-8x+2 is
MEDIUM
If one end of a focal chord of the parabola, y2=16x is at 1,4, then the length of this focal chord is
EASY
The vertex of the parabola y=(x-2)(x-8)+7 is
EASY
The vertex of the parabola y=x2-2x+4 is shifted p units to the right and then q units up. If the resulting point is (4,5), then the values of p and q respectively are
MEDIUM
Let A4,-4 and B9,6 be points on the parabola, y2=4x. Let C be chosen on the arc AOB of the parabola, where O is the origin, such that the area of ΔACB is maximum. Then, the area (in sq. units) of ΔACB , is:
EASY
The cartesian co-ordinates of the point on the parabola y 2 =16x, whose parameter is 12 are
EASY
The focus of the curve y2+4x-6y+13=0 is